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If y equals -4E-11x3 plus 2E-07x2 plus 9E-05x plus 0.062 what is x?
9E-05x
Cu---Cu plus 2 plus 2e- this equation above represents the type of reaction called?
oxidation
How do you solve 2e minus 12 equals 7e plus 8?
2e - 12 = 7e + 8Add 12 to both sides: 2e = 7e + 20 subtract 7e from both sides: -5e = 20 divide both sides by -5: e = -4
What is 18 plus 18 plus 18 plus 18?
72. 18*4=72
What is 18 plus 18 plus 18 plus 19 plus 23 plus 23 plus 24 plus 24 equals?
18+18+18+19+23+23+24+24=167
7f - 2e - 3f plus 4e?
It can be simplified to: 4f+2e
What is the standard reduction potential for the half reaction Zn2 plus plus 2e- equals Zn?
Zn2+ + 2e- <--> Zno -0.7618 V
Calculate the standard emf of a cell that uses the Mg Mg2 plus and Cu Cu2 plus half cell reactions at 25 degrees C?
Cu + Mg2 --------> Cu2 + Mg Cu --------------> Cu2 + 2e Mg2 + 2e --------> Mg Cu --------------> Cu2 + 2e (E = +0.35) Mg2 + 2e --------> Mg (E = -2.36V) +0.35 + (-2.36) = -2.01V --------------------------------------… Mg + Cu2 --------> Mg2 + Cu Mg --------------> Mg2 + 2e Cu2 + 2e --------> Cu Mg --------------> Mg2 + 2e (E = +2.36V) Cu2 + 2e --------> Mg (E = -0.35V) +2.36 + (-0.35) = +2.01V
2e-7f-3e-f plus 6e plus 6f?
Simplified is 5e-2f.
What is the overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu s?
The overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu is 76 V.
If y equals -4E-11x3 plus 2E-07x2 plus 9E-05x plus 0.062 what is x?
9E-05x
What is the oxidation half reaction for 2mg plus o2 equals 2mgo?
Mg equals Mg2+ plus 2e-
Cu---Cu plus 2 plus 2e- this equation above represents the type of reaction called?
oxidation
What is the reduction half reaction for Mg s ZnCl2 aq MgCl2 aq Zn s?
-2.37 V (apex) Chace
If zinc and iron are used to make a cell what half-reactions will occur for zn2 plus aq plus 2e- zn s e0 equals -0.76 v and for fe3 plus aq plus e- fe2 plus aq e0 equals 0.77 v?
Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)
How do you solve 2e minus 12 equals 7e plus 8?
2e - 12 = 7e + 8Add 12 to both sides: 2e = 7e + 20 subtract 7e from both sides: -5e = 20 divide both sides by -5: e = -4
If a2 plus b2 equals c2 and e equals mc2 then by combining the two you get e equals m times the quantity a2 plus b2 right?
E=mc^2A^2+B^2=C^2E/m=C^2=A^2+B^2E/m=A^2+B^2E=m(A^2+B^2)correct
