0
Add your answer:
Earn +20 pts
which equation is balance in a basic solution?
CIO H2O 2e- CI- 2OH
How much is 2e-05?
7
How do you integrate of e -2x?
To integrate e^(-2x)dx, you need to take a u substitution. u=-2x du=-2dx Since the original integral does not have a -2 in it, you need to divide to get the dx alone. -(1/2)du=dx Since the integral of e^x is still e^x, you get: y = -(1/2)e^(-2x) Well, that was one method. I usually solve easier functions like this by thinking how the function looked like before it was differentiated. I let f(x) stand for the given function and F(x) stand for the primitive function; the function we had before differentiation (the integrated function). f(x)= e-2x <-- our given function F(x)= e-2x/-2 <-- our integrated function Evidence: F'(x)= -2e-2x/-2 = e-2x = f(x) Q.E.D It's as simple as that.
How do you solve 2e minus 12 equals 7e plus 8?
2e - 12 = 7e + 8Add 12 to both sides: 2e = 7e + 20 subtract 7e from both sides: -5e = 20 divide both sides by -5: e = -4
What is 2e plus 8 equals 2a-12?
It is one linear equation in two unknown variables: e and a.
What is the standard reduction potential for the half reaction Zn2 plus plus 2e- equals Zn?
Zn2+ + 2e- <--> Zno -0.7618 V
What is the oxidation half reaction for 2mg plus o2 equals 2mgo?
Mg equals Mg2+ plus 2e-
Solve ex equals 2e1-2x?
meant to be e^x = 2e^1-2x
If y equals -4E-11x3 plus 2E-07x2 plus 9E-05x plus 0.062 what is x?
9E-05x
If a2 plus b2 equals c2 and e equals mc2 then by combining the two you get e equals m times the quantity a2 plus b2 right?
E=mc^2A^2+B^2=C^2E/m=C^2=A^2+B^2E/m=A^2+B^2E=m(A^2+B^2)correct
If zinc and iron are used to make a cell what half-reactions will occur for zn2 plus aq plus 2e- zn s e0 equals -0.76 v and for fe3 plus aq plus e- fe2 plus aq e0 equals 0.77 v?
Zn(s) → Zn2+(aq) + 2e- and Fe3+(aq) + e- → Fe2+(aq)
7f - 2e - 3f plus 4e?
It can be simplified to: 4f+2e
What is the reduction half reaction for Mg s ZnCl2 aq MgCl2 aq Zn s?
-2.37 V (apex) Chace
What is the oxidation half-reaction for 2Mg O2 2MgO?
Mg equals Mg2+ plus 2e-
What are the half-reactions for a galvanic cell with Zn and Mg electrodes?
Ni2+(aq) + 2e- Ni(s) and Mg(s) Mg2+(aq) + 2e-
