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2 plus 3a plus 9a?
It is: 12a+2 when simplified
How do you solve -21 equals 9a-15-3a?
-21 = 9a - 15 - 3a -6 = 6a -1 = a
What is 10a plus 3a-4a?
10a + 3a - 4a = 9a
How do you solve a squared minus 4 over 2 plus 6a times 3 plus 9a over a squared plus 5a plus 6?
In order to solve something, there needs to be an equation. If I have read your equation right you have: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) This looks like it needs to be simplified. There are two fractions being multiplied, so multiply the numerators and denominators together, giving: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) = ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) Now, simplify the polynomials to remove the squared terms and any common factors: a² - 4 = (a - 2)(a + 2) 2 + 6a = 2(1 + 3a) 3 + 9a = 3(1 + 3a) a² + 5a + 6 = (a + 3)(a + 2) Giving: ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) = ((a + 2)(a - 2)3((1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) This can now be simplified by cancelling out equivalent terms, giving: ((a + 2)(a - 2)3(1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) = ((a - 2)3) / (2(a+3)) = 3(a - 2) / 2(a + 3) = (3a - 6) / (2a + 6)
How do you factorise 3a2 plus 9a?
It is 3a(a+3) when factored
What is the answer to 2 plus 3A plus 9A?
2 + 3A + 9A = 2 + 12AThe numerical value depends on the value of 'A'.It changes whenever 'A' changes.
What is 3a² 3a²?
3a^2 + 3a^2 = 6a^2 3a^2 - 3a^2 = 0 3a^2 x 3a^2 = 9a^4 3a^2 divided by 3a^2 = 1
How do you factor -3 out of -3a 9a-21?
-3(a^2 - 3a + 7)
What is 3a squared?
9a- a number is squared when it is multiplied by itself, so 3a x 3a = 9a.
How do you factor a3-9a2 plus 3a?
a(a^2 - 9a + 3)
2 plus 3a plus 9a?
It is: 12a+2 when simplified
How do you solve -21 equals 9a-15-3a?
-21 = 9a - 15 - 3a -6 = 6a -1 = a
How do you factor 9a2 plus 42at plus 49t2?
9a^2 + 42at + 49t^2 = (3a + 7t)(3a + 7t)
What is 10a plus 3a-4a?
10a + 3a - 4a = 9a
What is 9a plus 21 equals?
9a+21 3(3a+7)
What is 3a plus 4b plus 6a plus 3b in algebra?
9a + 7b *remember to look and understand the letters!*
How do you solve a squared minus 4 over 2 plus 6a times 3 plus 9a over a squared plus 5a plus 6?
In order to solve something, there needs to be an equation. If I have read your equation right you have: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) This looks like it needs to be simplified. There are two fractions being multiplied, so multiply the numerators and denominators together, giving: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) = ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) Now, simplify the polynomials to remove the squared terms and any common factors: a² - 4 = (a - 2)(a + 2) 2 + 6a = 2(1 + 3a) 3 + 9a = 3(1 + 3a) a² + 5a + 6 = (a + 3)(a + 2) Giving: ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) = ((a + 2)(a - 2)3((1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) This can now be simplified by cancelling out equivalent terms, giving: ((a + 2)(a - 2)3(1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) = ((a - 2)3) / (2(a+3)) = 3(a - 2) / 2(a + 3) = (3a - 6) / (2a + 6)
