9a+21 3(3a+7)
3a squared plus nine = 19a. 3a to the second power = 9a plus 9 = 19a.
3(3a+b)
Find what you can divide both 6ax and 9a by.They can both be divided by 3, leaving 2ax and 3a.These can both be divided by a, leaving 2x and 3.So 6ax + 9a = 3a (2x + 3)The factors of 6ax + 9a are 3a and (2x + a)
(9a + 2)(9a + 2)
It is: 12a+2 when simplified
9a^2 + 42at + 49t^2 = (3a + 7t)(3a + 7t)
a(a^2 - 9a + 3)
9a + 7b *remember to look and understand the letters!*
10a + 3a - 4a = 9a
9a+21 3(3a+7)
3a squared plus nine = 19a. 3a to the second power = 9a plus 9 = 19a.
a + 3a + 5a = 180 9a =180 a = 20
3(3a+b)
It is 3a(a+3) when factored
3a^2 + 3a^2 = 6a^2 3a^2 - 3a^2 = 0 3a^2 x 3a^2 = 9a^4 3a^2 divided by 3a^2 = 1
-3(a^2 - 3a + 7)