9a+21 3(3a+7)
3a squared plus nine = 19a. 3a to the second power = 9a plus 9 = 19a.
Find what you can divide both 6ax and 9a by.They can both be divided by 3, leaving 2ax and 3a.These can both be divided by a, leaving 2x and 3.So 6ax + 9a = 3a (2x + 3)The factors of 6ax + 9a are 3a and (2x + a)
(9a + 2)(9a + 2)
a + 3a - 2 + 3a. Add the a + 3a + 3a = 7a. You can't combine the -2 & 7a so the solution is: 7a - 2.
It is: 12a+2 when simplified
9a^2 + 42at + 49t^2 = (3a + 7t)(3a + 7t)
a(a^2 - 9a + 3)
9a + 7b *remember to look and understand the letters!*
10a + 3a - 4a = 9a
9a+21 3(3a+7)
3a squared plus nine = 19a. 3a to the second power = 9a plus 9 = 19a.
a + 3a + 5a = 180 9a =180 a = 20
The value of 9a plus 3b is the sum of the products of 9 multiplied by the value of a and 3 multiplied by the value of b. This expression represents a linear combination of the variables a and b. To find the numerical value, you would need specific values assigned to a and b.
It is 3a(a+3) when factored
3a^2 + 3a^2 = 6a^2 3a^2 - 3a^2 = 0 3a^2 x 3a^2 = 9a^4 3a^2 divided by 3a^2 = 1
-3(a^2 - 3a + 7)