0
What else can I help you with?
What is 9a plus 21 equals?
9a+21 3(3a+7)
What is 3a sqared plus 9?
3a squared plus nine = 19a. 3a to the second power = 9a plus 9 = 19a.
How do you factorise 6ax plus 9a?
Find what you can divide both 6ax and 9a by.They can both be divided by 3, leaving 2ax and 3a.These can both be divided by a, leaving 2x and 3.So 6ax + 9a = 3a (2x + 3)The factors of 6ax + 9a are 3a and (2x + a)
How do you factor 81a2 plus 36a plus 4?
(9a + 2)(9a + 2)
Simplify a plus 3a-2 plus 3a?
a + 3a - 2 + 3a. Add the a + 3a + 3a = 7a. You can't combine the -2 & 7a so the solution is: 7a - 2.
2 plus 3a plus 9a?
It is: 12a+2 when simplified
How do you factor 9a2 plus 42at plus 49t2?
9a^2 + 42at + 49t^2 = (3a + 7t)(3a + 7t)
How do you factor a3-9a2 plus 3a?
a(a^2 - 9a + 3)
What is 3a plus 4b plus 6a plus 3b in algebra?
9a + 7b *remember to look and understand the letters!*
What is 10a plus 3a-4a?
10a + 3a - 4a = 9a
What is 9a plus 21 equals?
9a+21 3(3a+7)
What is 3a sqared plus 9?
3a squared plus nine = 19a. 3a to the second power = 9a plus 9 = 19a.
What is a plus 3a plus 5a equals 180?
a + 3a + 5a = 180 9a =180 a = 20
How do you factorise 3a2 plus 9a?
It is 3a(a+3) when factored
What is 3a² 3a²?
3a^2 + 3a^2 = 6a^2 3a^2 - 3a^2 = 0 3a^2 x 3a^2 = 9a^4 3a^2 divided by 3a^2 = 1
How do you factor -3 out of -3a 9a-21?
-3(a^2 - 3a + 7)
How do you solve a squared minus 4 over 2 plus 6a times 3 plus 9a over a squared plus 5a plus 6?
In order to solve something, there needs to be an equation. If I have read your equation right you have: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) This looks like it needs to be simplified. There are two fractions being multiplied, so multiply the numerators and denominators together, giving: (a² - 4)/(2 + 6a) x (3 + 9a)/(a² + 5a + 6) = ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) Now, simplify the polynomials to remove the squared terms and any common factors: a² - 4 = (a - 2)(a + 2) 2 + 6a = 2(1 + 3a) 3 + 9a = 3(1 + 3a) a² + 5a + 6 = (a + 3)(a + 2) Giving: ((a² - 4)(3 + 9a)) / ((2 + 6a)(a² + 5a + 6)) = ((a + 2)(a - 2)3((1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) This can now be simplified by cancelling out equivalent terms, giving: ((a + 2)(a - 2)3(1 + 3a))/(2(1 + 3a)(a + 3)(a + 2)) = ((a - 2)3) / (2(a+3)) = 3(a - 2) / 2(a + 3) = (3a - 6) / (2a + 6)
