1 times -2 = -2.
x^-1 * x^-1 =x^(-1 + -1) =x^-2 or alternatively: 1/x times 1/x =1/x^2 (1/x^2) is the same as (x^-2)
-1 to the power of four equals -1 times -1 times -1 times -1. -1 times -1 equals 1 (since a negative times a negative equals a positive). (1 to the power of 2) 1 times -1 equals -1 (since a negative times a positive equals a negative). (1 to the power of 3) -1 times -1 equals 1. (1 to the power of 4)
1/3 x -2 = -2/3
The answer is "negative three halfs." (- 3/2) or _ 1 1/2 The equation is: -2/3 (x) = 1 -x = 3/2 x = -3/2 (aka negative one and one half)
240
The result is 1.
negative 2 over 6
1.5 or 1 and 1/2
2 x -2 - 3 x 3 + -1 = (2 x -2) - (3 x 3) + (-1) = -4 - 9 - 1 = -14.
2 * (-2) - (-5) = 1
-9/2
2-1 x 2-2 = 2-1 + -2 = 2-3 = 1/8, or one eighth.
x^-1 * x^-1 =x^(-1 + -1) =x^-2 or alternatively: 1/x times 1/x =1/x^2 (1/x^2) is the same as (x^-2)
y = 1/2x y = 1/2 times x to the negative 1 ( 1/2 x^-1) The slope is from differential calculus: slope = dy/dx = -1/2 times x to the negative 2 = -1/2x^2
-1 to the power of four equals -1 times -1 times -1 times -1. -1 times -1 equals 1 (since a negative times a negative equals a positive). (1 to the power of 2) 1 times -1 equals -1 (since a negative times a positive equals a negative). (1 to the power of 3) -1 times -1 equals 1. (1 to the power of 4)
Negative plus a negative is a negative. Ex. -1+-1=-2 Negative times a negative is a positive. -2*-2=4 But a negative [minus] plus a positive [plus] can be minus, zero or plus: For example, -3 + 2 = -1 -3 + 3 = 0 -3 + 4 = +1
factors are the numbers you multiply together to get a product in a multiplication problem. a positive times a positive = a positive a positive times a negative = a negative a negative times a negative = a positive since you are looking for negative 10, you need one factor to be positive and one to be negative. this could be: -1*10 -10*1 -2*5 -5*2