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What is 2 x pi x 15?

Updated: 9/27/2023
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Q: What is 2 x pi x 15?
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What is the circumference of a 15 foot diameter circle?

47.1 feet Circumference = 2 x pi x r OR pi x d 3.14 x 15 feet = 47.1 feet


What is the surface area of a cylinder whose radius is 15 and height is 30?

The formular for the surface area of a cylinder is 2(pi)rh + 2(pi)r2 where r=radius and h=height and pi=3.14 SA= 2 x 3.14 x 15 x 30 + 2 x 3.14 x 152 =4239


What is the circumference of 15 cm circle?

Multiply the diameter by pi, which is approximately 3.14. If 15 cm. is the radius, multiply by 2 x pi.


What is the area of a circle of radius 15 cms?

It is pi x 15 x 15 = pi x 225 = 3.1415 x 225 = 706.84 square cms


How do you find a radius if you have the circumference?

You divide circumference / (2 x pi).You divide circumference / (2 x pi).You divide circumference / (2 x pi).You divide circumference / (2 x pi).


Radius of 5m what is the circumference?

If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.If you mean a circle: the circumference is equal to diameter x pi, or 2 x pi x radius.


Where pi is 3.14 Find the circumference of a circle whose radius is 15 centimeters?

circumference = 2 x π x radius = 2 x 3.14 x 15 cm = 94.2 cm


How do you multiply two times pi times two?

2 x pi x 2 = 4 x pi


The radius of a circle is x plus 4 what is the circumference?

Circumference = (2) x (pi) x (Radius)= (2 pi) times (X + 4)= same as (2 pi X) + (8 pi)= same as [ pi (2X + 8) ]


What is the circumference if the radius is 15?

Radius = 15Diameter = 2 x radius = 30Circumference = pi D = 30 pi = 94.25 (rounded)


How find area of a circle if diameter is 15?

pi * 225/4 Radius is 15/2 pi r2 = pi * (15/2)2 = pi * 225/4


Sin x - cos x 0 0?

sin x - cos x = 0sin x = cos x(sin x)^2 = (cos x)^2(sin x)^2 = 1 - (sin x)^22(sin x)^2 = 1(sin x)^2 = 1/2sin x = ± √(1/2)sin x = ± (1/√2)sin x = ± (1/√2)(√2/√2)sin x = ± √2/2x = ± pi/4 (± 45 degrees)Any multiple of 2pi can be added to these values and sine (also cosine) is still ± √2/2. Thus all solutions of sin x - cos x = 0 or sin x = cos x are given byx = ± pi/4 ± 2npi, where n is any integer.By choosing any two integers , such as n = 0, n = 1, n = 2 we can find some solutions of sin x - cos x = 0.n = 0, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(0)(pi) = ± pi/4 ± 0 = ± pi/4n = 1, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(1)(pi) = ± pi/4 ± 2pi = ± 9pi/4n = 2, x = ± pi/4 ± (2)(n)(pi) = ± pi/4 ± (2)(2)(pi) = ± pi/4 ± 4pi = ± 17pi/4