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How do you get a radius of a circumference?
The circumference of a circle is calculated by multiplying the radius by 2xPI PI is approximately 3.141 This means the radius can be calculated by dividing the circumference by 2xPI
How do you work out 2Pi r?
2xPi(3.14....)xradius
What is the circumference of a circle whose radius is 4.5 in?
Multiply the radius by 2xpi.
What is the radius if the curcumference is 23 inches?
Assuming we are talking about a circle... C = 2xpixr 23 = 2 x pi x r r = 23/(2xpi)
How can you find out if an equation has infinitely many solutions?
There are many different kinds of equations, and each kind requires special techniques for solving; so it probably isn't possible to give rules that are valid in all cases. In any case, here are some specific examples; I am sure there are others which I don't remember right now:Trigonometric equations quite often have an infinite number of solutions, because they are periodic. To give a simple example, sin x = 0 has the solution x = 0, but also pi, 2xpi, 3xpi, etc. (equivalent to 180 degrees, 360 degrees, etc.), because of the periodic nature of the sine function.If a variable disappears when solving an equation, if you get a true statement the solution set is the set of all real numbers. For example, 2(x+1) = 2x + 2. Solving, you get: 2x + 2 = 2x + 2, or 0 = 0. Note that the variable "x" disappeared.There are many different kinds of equations, and each kind requires special techniques for solving; so it probably isn't possible to give rules that are valid in all cases. In any case, here are some specific examples; I am sure there are others which I don't remember right now:Trigonometric equations quite often have an infinite number of solutions, because they are periodic. To give a simple example, sin x = 0 has the solution x = 0, but also pi, 2xpi, 3xpi, etc. (equivalent to 180 degrees, 360 degrees, etc.), because of the periodic nature of the sine function.If a variable disappears when solving an equation, if you get a true statement the solution set is the set of all real numbers. For example, 2(x+1) = 2x + 2. Solving, you get: 2x + 2 = 2x + 2, or 0 = 0. Note that the variable "x" disappeared.There are many different kinds of equations, and each kind requires special techniques for solving; so it probably isn't possible to give rules that are valid in all cases. In any case, here are some specific examples; I am sure there are others which I don't remember right now:Trigonometric equations quite often have an infinite number of solutions, because they are periodic. To give a simple example, sin x = 0 has the solution x = 0, but also pi, 2xpi, 3xpi, etc. (equivalent to 180 degrees, 360 degrees, etc.), because of the periodic nature of the sine function.If a variable disappears when solving an equation, if you get a true statement the solution set is the set of all real numbers. For example, 2(x+1) = 2x + 2. Solving, you get: 2x + 2 = 2x + 2, or 0 = 0. Note that the variable "x" disappeared.There are many different kinds of equations, and each kind requires special techniques for solving; so it probably isn't possible to give rules that are valid in all cases. In any case, here are some specific examples; I am sure there are others which I don't remember right now:Trigonometric equations quite often have an infinite number of solutions, because they are periodic. To give a simple example, sin x = 0 has the solution x = 0, but also pi, 2xpi, 3xpi, etc. (equivalent to 180 degrees, 360 degrees, etc.), because of the periodic nature of the sine function.If a variable disappears when solving an equation, if you get a true statement the solution set is the set of all real numbers. For example, 2(x+1) = 2x + 2. Solving, you get: 2x + 2 = 2x + 2, or 0 = 0. Note that the variable "x" disappeared.
How do you get a radius of a circumference?
The circumference of a circle is calculated by multiplying the radius by 2xPI PI is approximately 3.141 This means the radius can be calculated by dividing the circumference by 2xPI
How do you work out 2Pi r?
2xPi(3.14....)xradius
What is the circumference of a circle whose radius is 4.5 in?
Multiply the radius by 2xpi.
Find the circumference of a circle?
If you know the diameter, multiply it by pi. If you know the radius, multiply it by 2xpi. Pi is approximately 3.1416.
What is means by propagation constant definition?
It's a scientific term (mathematical) used to describe wave propagation. It is equal to 2π (2xPi) divided by the wavelength
If the circumference of a circle is 2053 feet what is the radius of the circle?
Given the circumference of a circle the radius is: r = C / 2xPI So the radius of your circle is 326.7451 ft
What is the radius if the curcumference is 23 inches?
Assuming we are talking about a circle... C = 2xpixr 23 = 2 x pi x r r = 23/(2xpi)
Why an irrational number plus an irrational number equal a rational?
That simply isn't true. The sum of two irrational numbers CAN BE rational, but it can also be irrational. As an example, the square root of 2 plus the square root of 2 is irrational.
What is the circumference of the circular table whose radius is 56.12?
Multiply by 2xpi (that is, by about 44/7) to get 352.75 To find the circumference of an object, you take it's diameter and multiply it by pi. If we take an approximate pi (3.14), and multiply it by the diameter (which is 56.12 multiplied by 2, or 112.24), we get the formula: C=pi(d) C=3.14(112.24) C=352.4336 Therefore, the circumference of the table is about 352.4336 units
How can you find out if an equation has infinitely many solutions?
There are many different kinds of equations, and each kind requires special techniques for solving; so it probably isn't possible to give rules that are valid in all cases. In any case, here are some specific examples; I am sure there are others which I don't remember right now:Trigonometric equations quite often have an infinite number of solutions, because they are periodic. To give a simple example, sin x = 0 has the solution x = 0, but also pi, 2xpi, 3xpi, etc. (equivalent to 180 degrees, 360 degrees, etc.), because of the periodic nature of the sine function.If a variable disappears when solving an equation, if you get a true statement the solution set is the set of all real numbers. For example, 2(x+1) = 2x + 2. Solving, you get: 2x + 2 = 2x + 2, or 0 = 0. Note that the variable "x" disappeared.There are many different kinds of equations, and each kind requires special techniques for solving; so it probably isn't possible to give rules that are valid in all cases. In any case, here are some specific examples; I am sure there are others which I don't remember right now:Trigonometric equations quite often have an infinite number of solutions, because they are periodic. To give a simple example, sin x = 0 has the solution x = 0, but also pi, 2xpi, 3xpi, etc. (equivalent to 180 degrees, 360 degrees, etc.), because of the periodic nature of the sine function.If a variable disappears when solving an equation, if you get a true statement the solution set is the set of all real numbers. For example, 2(x+1) = 2x + 2. Solving, you get: 2x + 2 = 2x + 2, or 0 = 0. Note that the variable "x" disappeared.There are many different kinds of equations, and each kind requires special techniques for solving; so it probably isn't possible to give rules that are valid in all cases. In any case, here are some specific examples; I am sure there are others which I don't remember right now:Trigonometric equations quite often have an infinite number of solutions, because they are periodic. To give a simple example, sin x = 0 has the solution x = 0, but also pi, 2xpi, 3xpi, etc. (equivalent to 180 degrees, 360 degrees, etc.), because of the periodic nature of the sine function.If a variable disappears when solving an equation, if you get a true statement the solution set is the set of all real numbers. For example, 2(x+1) = 2x + 2. Solving, you get: 2x + 2 = 2x + 2, or 0 = 0. Note that the variable "x" disappeared.There are many different kinds of equations, and each kind requires special techniques for solving; so it probably isn't possible to give rules that are valid in all cases. In any case, here are some specific examples; I am sure there are others which I don't remember right now:Trigonometric equations quite often have an infinite number of solutions, because they are periodic. To give a simple example, sin x = 0 has the solution x = 0, but also pi, 2xpi, 3xpi, etc. (equivalent to 180 degrees, 360 degrees, etc.), because of the periodic nature of the sine function.If a variable disappears when solving an equation, if you get a true statement the solution set is the set of all real numbers. For example, 2(x+1) = 2x + 2. Solving, you get: 2x + 2 = 2x + 2, or 0 = 0. Note that the variable "x" disappeared.
A wheel has a radius of 4.3 m How far path length does a point on the circumference travel if the wheel is rotated through angles of 30 30 rad and 30 rev respectively?
The diameter (i.e. the length of the outside) of the wheel is 4.3 meters times Pi (3.14) or abut 13.5 meters.Circumference = 4.3 m x Pi = 4.3 x 3.14 = 13.5mFor a 30 degree rotation, the wagon will have moved forward a fraction of the wheel's circumference that is equal to the percentage of the wheel thatis represented by 30degrees. Since the circumference is represented by 360 dgrees, this percetange is 30/360.Distance moved = (percentage of circumference represented by 30 degrees)x(circumference)= (30 degrees/360 degrees)x(13.5m) = 1.125m or 1-1/8mFor a 30 rad rotation (rad=radians) , the wagon will have moved forward a multiple of the wheel's circumference that is equal to the multiple that is represented by 30radians. Since the there 2 times Pi radians per 360 degrees, there are 2xPi radians per circumference.Thirty radians (in terms of circumference) = (number of radians)/radians per one circumference) =(30 radians)(1 circumference/2 x Pi radians) =15/Pi circumferencesDistance moved = (multiple of circumference represented by 30 radians)x(circumference)= (15/Pi circumferences)x(4.3m x Pi) = 15x4.3 m = 64.5mFor 30 revolutions, the wagon will have moved forward 30 times the wheel's circumference because one revolution is equal to one circumference.Thirty revolutions = number of revolutions x (number of circumferences/revolution) = 30 rev x (1 rev/1 circumference) = 30 circumferencesDistance moved = (30 circumferences)x(13.5m) = 405m
How do you find the circumference of a circle Is it PIE times diameter times 2?
Dear confused (not in a rude way, u do seem confused),Circumference=2xPIxR..............is the best way.For example,If the R (radius) is 20m and PI is 3.14 then you times PI 2 times which is 2xPI (3.14)=6.28, THEN YOU times 6.28 by the R (radius)=125.6m rounded to 1 decimal place will leave you with 125.7m and that will be the circumference.With all the best, FatimaThe above equation |2×Pi×r = circumference| is correct.The explanation however, is misleading- primarily the two words written IN CAPS. "THEN YOU"If everything in a formula, or on one side of an equation is being added, subtracted or multiplied, you are free to solve in any order you choose. This rule does NOT apply to division.The communative property for multiplicationstates that for any numbers a and b, the following is always true:(a×b) == (b×a)The associative property for multiplication states that for any numbers a , b, and c , the following is always true:(a×b)×c == a×(b×c)given that the above are true, the following are also true of our equation...2 × Pi × r 2 × (r × Pi)using the same example from above, you're given a circle with a radius = 20m.(2 × 3.14) × 20 == 2 × (3.14 × 20)plug in Pi(3.14) and r(20) and then choose the order in which you wish to multiply. Think of the commutative property as what it is. The freedom to commute through the steps in any order.(2 × 3.14) = (6.28)×20 = 125.6mis the same as... (using the associativeproperty)(3.14 × 20) = (62.8)×2 = 125.6mis the same as... (using the commutative property)(20 × 3.14) = (62.8)×20 = 125.6mis the same as... oh I dunno... (still using the commutative property)(2 × 20) = (40)×3.14 = 125.6mLooking carefully at the order of the last formula, we actually formed a 'new' equation...Multiplying (2 × radius(20)),(2_×_20)gave us the diameter(40), which we then multiplied by Pi(40)×3.14to get the circumference(125.6m).= 125.6mIf you have the diameter, don't waste your time with 2*r*Pi. Use the equationd×Pi = circumference
