Q: How do you work out 2Pi r?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

a(r) = 2pi*r^2 and d = 2r 5 = 2r => r = 5/2 a(r) = 2pi*(5/2)^2 a(r) = 2pi*25/4 a(r) = 25pi/2 or, in decimal form, 39.2699 millimetres2

Circumference = 2*pi*raduis 16 = 2*pi*r divide both sides by 2pi 16/2pi = r 8/pi = radius

Circumference = 2pi*r 410 = 2pi*r r = 205/pi A = pi*r^2 A = pi*(205/pi)^2 A = 205^2/pi metres A = 42 025/pi metres

The formula for surface area of a cylinder is (2pi * r^2) + (2pi * r * h). Substituting your values in, the surface area would be 170pi.

Use this formula where r is the radius: C = 2Pi(r)

Related questions

No. 2Pi r is equal to Pi d, though.

The circumference of a circle C is 2Pixr So solving for r we have C/2Pi=r

a(r) = 2pi*r^2 and d = 2r 5 = 2r => r = 5/2 a(r) = 2pi*(5/2)^2 a(r) = 2pi*25/4 a(r) = 25pi/2 or, in decimal form, 39.2699 millimetres2

Surface area you mean? Then 2pi*r2 + 2pi*r*h where h=height and r=radius

it is the formula of circumference of circle

To convert area into circumference, take the two formulas for circles--circumference and area: C=2pi*r A=pi*r^2 Now, isolate the common variable (r) in the second equation. r=sqrt(A/pi) Now you can substitute this in for "r" in the first equation to find circumference C=2pi*sqrt(A/pi) C=2pi*sqrt(36pi/pi) pi cancels out C=2pi*sqrt(36) C=2pi*6 C=12pi

Circumference = 2pi*r 26.69/2pi = 4.248m (rounded to three decimal places)

2 * area of circle + circumference * height 2 * pi*r^2 + 2pi*r * h 2pi*8^2 + 2pi*8*30 128pi + 480pi 608pi

C = 2(pi)(r) so that r = C/(2pi) = 135/(2pi) ≈ 21.5 ft.

Circumference = 2*pi*raduis 16 = 2*pi*r divide both sides by 2pi 16/2pi = r 8/pi = radius

Circumference = 2pi*r 410 = 2pi*r r = 205/pi A = pi*r^2 A = pi*(205/pi)^2 A = 205^2/pi metres A = 42 025/pi metres

Length of outer track = sum of length of 10 pieces = circumference of the outer circleif R is the Radius of outer circle then...Circumference of the outer track = 2pi*RSimilarly the circumference of the inner track (with radius r) = 2pi*rlength of each outer piece is 3.4 inch more than length of inner pieceSo total outer length is 10*3.4 =34 inches more than the inner length.=> Outer Circumference - Inner Circumference = 34 inches=> 2pi*R - 2pi*r = 34=> 2pi(R -r) = 34=> R-r = 34/2pi = 5.41 inches=> R-r = Width of the track = 5.41 inches1 year ago