3,492,834 multiplied by 333,333 is 1,164,276,835,722
There are infinitely many pairs of number. Let A be any number and let B = A + 333333.Then B - A = A + 333333 - A = 333333.Since The choice of A is arbitrary so A could be any one of infinitely many numbers. Therefore, there are infinitely many solutions.
3,3,7,11,13, and 37
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333,333 = 3.33333 × 105
For short stretches, yes, certainly. For example, there are 9 stretches of a number repeating 6 or more times (eg 333333) in the first million digits. Similarly, you can get 212121. But sooner or later the pattern and its repeat diverge. For short stretches, yes, certainly. For example, there are 9 stretches of a number repeating 6 or more times (eg 333333) in the first million digits. Similarly, you can get 212121. But sooner or later the pattern and its repeat diverge. For short stretches, yes, certainly. For example, there are 9 stretches of a number repeating 6 or more times (eg 333333) in the first million digits. Similarly, you can get 212121. But sooner or later the pattern and its repeat diverge. For short stretches, yes, certainly. For example, there are 9 stretches of a number repeating 6 or more times (eg 333333) in the first million digits. Similarly, you can get 212121. But sooner or later the pattern and its repeat diverge.
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