That would be 3 x 10^14 .
In Hexadecimal "A" is a representation of 10
6. If the number has a decimal, starting from the left and moving to the right find the first nonzero digit. From there, count every single digit you come across (even other zeros). The number of digits you count is the number of significant figures.
When the last digit of a significant digit is 5, you always round up.
It could mean different things depending on the context. In computing for example, it is a value - either a 1 or a 0, otherwise known as a binary digit or a bit.
Any digit in a number which is to the right of the first digit which isn't a zero, including the first digit
3.94 x 10^-6
6 x 10^10
5 x 10^-9
0.0000000734 = 7.34 x 10^-8 ≈ 7 x 10^-8
679 is the product of the largest single-digit prime number and the largest two-digit prime number.
The only pair of positive single-digit numbers which give a product of 81 are 9 and 9.
the estimated digit in 0.0782m is?
A single number cannot produce a product.
There need no be any estimated digit.
99, I would say.
362,880 edit: 3,628,800 edit: Sorry, Whizkid. You included '10', whereas the question clearly stated "single-digit numbers". Now that we think about it, the "10 single digit numbers" must include zero, so the product is zero. But for the digits 1 thru 9, the product is still 362,880 .
The last digit is always the estimated digit in a number