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There need not be any estimated digit but, if there must be one, then it is the last digit: 3.

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What is the unit of measurement for finding the capacity?

mL and L


How do you calculate the hypotenuse of a right triangle?

The old pythagorean theorem says, "the square of the hypotenuse is equal to the sum of the square of the other two sides." What that means is, get an accurate measurement of the two sides that touch the right angle, square them and add them together then take the square root of that number and you'll have the length of the hypotenuse. In mathematical terms it's: A2+ B2= C2. The hypotenuse of a right angled triangle is the longest side, or the one opposite the right angle. It can be calculated using a variety of methods - Pythagoras theorem : A2 + B2 = C2, where A and B are the sides adjacent to the right angle, and C is the hypotenuse. The square of A plus the square of B is equal to the square of C, so C can be calculated as √(A2 + B2). Trigonometric angle rules : Sin(e) x = o/h, cos(ine) x = a/h, tan(gent) x = o/a, where x is one of the other two angles, o is the side opposite this angle, a is the side adjacent to it, and h is the hypotenuse. Using these angle rules, you can calculate the length of any of the sides given the length of one of the other sides plus an angle. There are others, but they start to become more difficult to explain without other knowledge in triangle geometry! a2+b2=c2 /l / l / l C / l A / l / l / l /____ l B Example: /l / l / l C / l A=4 / l / l / l /___ l B=3 a2+b2=c2 42+32=c2 16+9=c2 25=c2 square root of 25= square root of c2 5=c Answer: /l / l / l C=5 / l A=4 / l / l / l /____ l B=3 Formula: a2+b2=c2 Example: A=4 B=3 C=? a2+b2=c2 42+32=c2 16+9=c2 25=c2 square root of 25= square root of c2 5=c Answer: A=4 B=3 C=5


L 7-3 l - l 3 - 7 l equals?

If these are meant to be the difference of two absolute quantities, the answer is zero.


What is the area of a rectangle with a perimeter of 40 m and a length of 8m?

Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2Perimeter = 40So 2*(L + B) = 40 therefore L + B = 20Then L = 8 gives B = 12Therefore the Area is L*B = 8*12 = 96 m2


How do you find the perimeter of a rectangle when given area?

You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.

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