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Q: What is 35 div ion by 7?

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a) first find how many numbers are divisible by 5 and 7 separately add them and subtract that are divisible by both 7 and 5 ie 35.the result subtract from 1000 to get the answer to your first question nos. divisible by 5 . last no. div by 5 is 995 .hence we have 995 = 0 + ( n-1) 5 which gives 200 . last no div by 7 is 994 .hence 994 = 0+ ( n-1) 7 which gives n = 143 . nos div by both 5 and 7 .last no div by 35 is 980. 980 = 0+ (n-1) 35 which gives n= 29 hence there are 200+ 143- 29 = 314 numbers div by 5 or 7 a) not div by 5or 7 = 1000- 314 = 686 b)div by 5 and7 =29 c) div by 5 or 7 = 314 d) div by 5 and not by 7 = 200-29 = 171 so answer is 686 Amit singh

Sum(not div by 7) = Sum(all) - Sum(div by 7) Now the sum of an AP is Sn = n/2 (first + last) where n is the number of terms Sum(All) = 10000/2 (1 + 10000) = 50005000 Sum(div by 7) = (9996/7)/2 (7 + 9996) = 1428/2 (10003) = 7142142 Sum(not div by 7) = Sum(all) - Sum(div by 7) = 50005000 - 7142142 = 42 862 858

No they have 7 u div:)

An ion with 35 protons and 38 electrons has a charge of -3.

35 and 7, respectively.

35

It's not that hard. If this is what you mean: <div> <div> <h1>Some content</h1> </div> </div>

There are 35 protons. And there are 35 electrons.

7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.7 hours and 35 minutes.

<html> <body> <div></div> </body> </html> that is an empty div tag, there is nothing in between the <div> and </div>

7 is a factor of 35.

7/35 7/7=1 35/7=5 7/35=1/5 1/5=0.2

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