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How many numbers from between 0 or 999 are not divisible by either 5 or 7?
a) first find how many numbers are divisible by 5 and 7 separately add them and subtract that are divisible by both 7 and 5 ie 35.the result subtract from 1000 to get the answer to your first question nos. divisible by 5 . last no. div by 5 is 995 .hence we have 995 = 0 + ( n-1) 5 which gives 200 . last no div by 7 is 994 .hence 994 = 0+ ( n-1) 7 which gives n = 143 . nos div by both 5 and 7 .last no div by 35 is 980. 980 = 0+ (n-1) 35 which gives n= 29 hence there are 200+ 143- 29 = 314 numbers div by 5 or 7 a) not div by 5or 7 = 1000- 314 = 686 b)div by 5 and7 =29 c) div by 5 or 7 = 314 d) div by 5 and not by 7 = 200-29 = 171 so answer is 686 Amit singh
Find the sum of all positive integers not greater than 10000 that are not divisible by 7?
Sum(not div by 7) = Sum(all) - Sum(div by 7) Now the sum of an AP is Sn = n/2 (first + last) where n is the number of terms Sum(All) = 10000/2 (1 + 10000) = 50005000 Sum(div by 7) = (9996/7)/2 (7 + 9996) = 1428/2 (10003) = 7142142 Sum(not div by 7) = Sum(all) - Sum(div by 7) = 50005000 - 7142142 = 42 862 858
Is 7 not a factor of 35?
7 is a factor of 35.
How do you divide 7 into 35?
7/35 7/7=1 35/7=5 7/35=1/5 1/5=0.2
What is the Perimeter of a 4 X 6 square?
This is a trick question. A square by definition has four equal sides, therefore it cannot measure 4 x 6. A geometrical figure having four sides, right angles, and measuring 4 x 6 would be called a rectangle, not a square. And it would have a perimeter of 20. <p></p><p> </p>The definition of a square is that all four sides are equal.<div><br></div><div>Therefore your 4x6 is a rectangle, and not a square.</div><div><br></div><div>Perimeter would therefore be</div><div><br></div><div>4+6+4+6= 20.<div></div><div><br></div><div>Total all four sides of the rectangle. </div></div>
How many numbers from between 0 or 999 are not divisible by either 5 or 7?
a) first find how many numbers are divisible by 5 and 7 separately add them and subtract that are divisible by both 7 and 5 ie 35.the result subtract from 1000 to get the answer to your first question nos. divisible by 5 . last no. div by 5 is 995 .hence we have 995 = 0 + ( n-1) 5 which gives 200 . last no div by 7 is 994 .hence 994 = 0+ ( n-1) 7 which gives n = 143 . nos div by both 5 and 7 .last no div by 35 is 980. 980 = 0+ (n-1) 35 which gives n= 29 hence there are 200+ 143- 29 = 314 numbers div by 5 or 7 a) not div by 5or 7 = 1000- 314 = 686 b)div by 5 and7 =29 c) div by 5 or 7 = 314 d) div by 5 and not by 7 = 200-29 = 171 so answer is 686 Amit singh
Find the sum of all positive integers not greater than 10000 that are not divisible by 7?
Sum(not div by 7) = Sum(all) - Sum(div by 7) Now the sum of an AP is Sn = n/2 (first + last) where n is the number of terms Sum(All) = 10000/2 (1 + 10000) = 50005000 Sum(div by 7) = (9996/7)/2 (7 + 9996) = 1428/2 (10003) = 7142142 Sum(not div by 7) = Sum(all) - Sum(div by 7) = 50005000 - 7142142 = 42 862 858
Do all birds have forelegs?
No they have 7 u div:)
What is the LCM and the GCF of 35 and 7?
35 and 7, respectively.
How can you use div under div?
It's not that hard. If this is what you mean: <div> <div> <h1>Some content</h1> </div> </div>
How many electrons does bromide ion have?
The element bromine has an atomic number of 35. This means that each atom contains 35 protons, and the requirement for electrical neutrality in an atom means that the atom also contains 35 electrons. A bromide ion contains one more electrons than a bromine atom: 36.
How can you see the php code that is executed in your browser?
May be this example will help. Please focus on where ob_implicit_flush(true) and ob_end_flush(); are placed in your code. Version 1:-------------------------------- <?PHP ob_implicit_flush(true); ob_end_flush(); ?> e <div>a<div>a</div> <?PHP sleep(1); ?> <div>b</div> <?PHP sleep(1); ?> c</div> Version 2:------------------------------ <?PHP ob_implicit_flush(true); ob_end_flush(); ?> e<div>a<div>a</div></div> <?PHP sleep(1); ?> <div>b</div> <?PHP sleep(1); ?> c</div> Version 3:------------------------------ <?PHP ob_implicit_flush(true); ob_end_flush(); ?> e<div>a<div>a</div><!--</div>--> <?PHP sleep(1); ?> <div>b</div> <?PHP sleep(1); ?> c</div> ?>
How many protons and electrons in ion Br?
35 protons, 36 electrons
Is 7 not a factor of 35?
7 is a factor of 35.
How do you divide 7 into 35?
7/35 7/7=1 35/7=5 7/35=1/5 1/5=0.2
The ion ICl4- has how many valence electrons?
The ICl4- ion has 36 valence electrons. Iodine contributes 7 valence electrons and each chlorine atom contributes 7 valence electrons, totaling 36 valence electrons in the ICl4- ion.
What is the quotient of 35 divided by 5 and 7?
35/7=5 35/5=7. The question is the quotient of 35/5 and 7
