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Anonymous
(3x - 3)(x/6)(x2 - x)= (3)(x - 1)(x/6)(x)(x - 1)
= (1/2)(x2)(x -1)2
= (1/2)(x2)(x2 - 2x + 1)
= (1/2)x4 - x3 + (1/2)x2
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