(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
Quotient: 2x3-x2-14x+42 Remainder: -131 over (x+3)
5(x + 2y2)(x2 - 2xy2 + 4y4)
This is an expression and you do not solve an expression, but you can factor this one.X2 + 3X4X2(1 + 3X2)========
it is 3. You are doing APEX right?
-6x3 + 4x7 - 0.8x2 + x4 - 5x5 = 4x7 - 5x5 + x4 - 6x3 - 0.8x2 = x2 (4x5 - 5x3 + x2 - 6x - 0.8)
i got 42 divided 7x
Since 5x is a factor of both terms, divide it. 5x3 + 5x = 5x(x2 + 1)
Given 3x3 + 4x2 +x + 7 is divided by x2 + 1, find the results:
3x2(x2 - 3)