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This is an expression and you do not solve an expression, but you can factor this one.
X2 + 3X4
X2(1 + 3X2)
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∙ 11y ago
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What is 3x4 plus 5x3 plus x2 - 5 divided by x 2?
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
What is the answer for x2 plus 1 plus 3x4 equals 2?
-7.5?
What is the expntents of x5 - 3x4 plus x2 - 4 plus 5x4 plus 3x2 plus 2x plus 1?
x^5+2x^4+4x^2+2x-3
Factor the expression 3x4-9x2?
3x2(x2 - 3)
Solve the equation y' plus x2y equals x2?
(2x)ysquared
What is 3x4 plus 5x3 plus x2 - 5 divided by x 2?
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
What is the answer for x2 plus 1 plus 3x4 equals 2?
-7.5?
Quotient and remainder of 3X4 plus 2X3 minus X2 minus x minus 6 divided by X2 plus 1?
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
How do you solve x2 plus 7x plus 12?
x2+7x+12
What is the coefficient of the term of degree 4 in this polynomial 2x5 plus 3x4 - x3 plus x2 - 12?
it is 3. You are doing APEX right?
How do you solve x2 plus 3x plus 3 0?
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
What is the expntents of x5 - 3x4 plus x2 - 4 plus 5x4 plus 3x2 plus 2x plus 1?
x^5+2x^4+4x^2+2x-3
X6 plus 3x4-x2-3 equals 0?
x6 + 3x4 - x2 - 3 = 0(x6 + 3x4) - (x2 + 3) = 0x4(x2 + 3) - (x2 + 3) = 0(x2 + 3)(x4 - 1) = 0(x2 + 3)[(x2)2 - 12] = 0(x2 + 3)(x2 + 1)(x2 - 1) = 0(x2 + 3)(x2 + 1)(x + 1)(x - 1) = 0x2 + 3 = 0 or x2 + 1 = 0 or x + 1 = 0 or x - 1 = 0x2 + 3 = 0x2 = -3x = ±√-3 = ±i√3 ≈ ±1.7ix2 + 1 = 0x2 = -1x = ±√-1 = ±i√1 ≈ ±ix + 1 = 0x = -1x - 1 = 0x = 1The solutions are x = ±1, ±i, ±1.7i.
Factor the expression 3x4-9x2?
3x2(x2 - 3)
Solve the equation y' plus x2y equals x2?
(2x)ysquared
How do you solve X2 plus x-132?
-130
Solve x2 plus 10x plus 25?
(x+5)^2 and therefore x = -5
