The product is 328
1 times 41 = 41 which is also a prime number.
5 with 1 remaining 41 - 1 = 40 = 8 x 5
8
Eight times.
8, remainder 16
41 times with a remainder of 8
41 ÷ 5 = 8 with remainder 1
8 with remainder 41.
8 1/5 x 5 is 41
943/96
To create a PEMDAS problem that equals 41, you can use the following example: ( (8 \times 5) + (12 \div 3) = 41 ). This simplifies to ( 40 + 4 = 41 ). Another example is ( 100 - (3^2 \times 7) = 41 ), which simplifies to ( 100 - 63 = 41 ).
Because 8 goes into 41 5 times evenly, with one left over. (5 x 8 = 40) and (41 - 40 = 1)