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What is 42 days after 18 May 2007?

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Anonymous

15y ago
Updated: 8/17/2019

June 27, 2007

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15y ago

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'A' does (1/14) of the job in 1 day. 'B' does (1/21) of the job in 1 day.'B' worked alone for the last 3 days. In that time, he did the last (3/21) of the job.So the part they did together was the first (18/21) of the total job.Working together, they do (1/14 + 1/21) = (3/42 + 2/42) = (5/42) of the job each day.If the number of days they worked together was 'D', then (5/42)D = (18/21).D = (18/21) / (5/42) = (18/21) x (42/5) = (18 x 42 / 21 x 5) = 36/5 = 7.2 days.They worked together for 7.2 days. Then 'A' left. and 'B' worked alone for 3 days.The work was completed in (7.2 + 3) = 10.2 days.=========================================Check:[ (7.2) x (5/42) ] + (3/21) = (36/42) + (3/21) = (36/42) + (6/42) = (42/42) = 1 job yay!


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