42 is divisible by: 1 2 3 6 7 14 21 and 42.
The divisibility rule for 42 isdivisibility by 2, ANDdivisibility by 3, ANDdivisibility by 7.Divisibility by 2 requires the number to be even. That means it must end in 0, 2, 4, 6 or 8.Divisibility by 3 requires that the digital root of the number is divisible by 3. That is, the sum of the digits is divisible by 3. If the first sum is large, you can calculate the digital root of the digital root (and again, if necessary) and check that for divisibility by 3.The divisibility rule for 7 is more difficult.Take the last digit (units).From the number formed by the remaining digit, subtract twice the last digit.If the answer is divisible by 7 (including zero or negative numbers), then the original number is divisible by 7.For large numbers, repeat the process to bring the number down to a manageable size.
Divisibility is what a number can be divided by.
It is somebody talking about divisibility.
By tautology. If it did not work, it would not be a divisibility rule!
You are looking for the prime factorization of 42. Since 42 is definetely even, we conduct a test on the divisibility of 3 first. 4 + 2 = 6, and 6 mod 3 = 0. Therefore, it is divisible by 6. 6 factors to 3 and 2, and when 42/6 = 7, which is a prime. Therefore, the product is: 3 * 2 * 7.
There are two ways of answering this.Check the number for divisibility by 2.Check the quotient for divisibility by 2.Check the quotient for divisibility by 2.Check the quotient for divisibility by 2.Check the quotient for divisibility by 2.Check the quotient for divisibility by 2.For large numbers, the check can be restricted to the number formed by the last six digits.
A number is a multiple of 42 if it's a multiple of 2 and 21 at the same time 126 is a multiple of 42 because it ends in 6, which means it's a multiple of 2, and 12 - 6 x 2 = 0, which means it's a multiple of 21
There is no easy rule for divisibility by 34.
First, using your 2 divisibility rule, we find that both are even, therefore both are divisible by 2. Now, using the 3 divisibility rule, we know that 1 + 2 + 8 + 1 = 12, and 4 + 2 = 6, both multiples of 3. Thus, it must be divisible by 3 and 2, and it must divisible by 6! If so, then dividing both by 6 yields:1218/6 = 203, 42/6 = 7.Now both values are prime, therefore, 6 is the GCF of 1218 and 42.
It is divisibility by 3 and divisibility by 5.Divisibility by 3: the digital root of an integer is obtained by adding together all the digits in the integer, with the process repeated if required. If the final result is 3, 6 or 9, then the integer is divisible by 3.Divisibility by 5: the integer ends in 0 or 5.
2,3,9,6
No