What is the numerical value of 19 and 201 tenthousandths
7 tenthousandths + 4 thousandths + 6 tenths
No. It equals 4 amu.
Episode 26
0.0001
4 amu = 4*1.66054*10^-27 = 6.6422*10^-27 kilograms
0.0050
i think its episode 26
In the atom: Neutron: Mass: 1,00866491600(43) amu. Electron: Mass: 5,4857990946(22)×10−4 amu. Proton: Mass: 1,007276466812(90) amu.
Proton: 1.007276466812(90) amu. Neutron: 1.00866491600(43) amu. Electron: 5,857990946(22)×10−4 amu.
Given : Atomic mass of B = 10.01 amu , % = 19.9 let it be A Atomic mass of B = 11.01 amu , % = 80.1 Solution : A and B are approximately in the ratio 1:4. Isotopic mass = [(proportion of A X at. mass of A) + (proportion of B X at. mass of B)] / 4 = [(1 X 10.01) + (4 X 11.01)] / 4 = (10.01 + 44.04) / 4 = 54.05 / 4 Isotopic atomic mass = 13.512 amu ---- Therefore, isotopic atomic mass of B is = 13.512 amu.
5/10000 = 0.0005