Q: What is 4 plus root3?

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4 X 24 is 96ha ha ha

You cannot prove that sqrt(3)/2 = 0 because it is simply not true! The solution to the equation is theta (or, tita as you like to call it) = pi/6c or 30 degrees. The cosine of that angle is sqrt(3)/2 but that is NOT the same as it being 0.

Yes, irrational. Let p = root 2 and q = root 3. Then (q - p)2 = 5 - 2root6, which is irrational because it is the sum of an integer (5) and an irrational (2root6), and so q - p (which is root3 - root2) is irrational.

900042

69 its so freakin easy

Related questions

2-root3 = -1

The value of root3 in math is 1.732

5 Square root 3. square root 27 = square root 9*3 = 3square root 3 3square root3 + 2square root3 = 5Square Root3 because both have a square root 3.

2tan(x) + 2√3 = 3√3 2tan(x) = √3 tan(x) = √3 / 2 x = atan(√3 / 2) x ≈ 0.71372437894476563082

a/root3

root 3 = 1.732 (use your calculator) root 5 = 2.236 root3 + root5 = 3.968 =========================

It is simple. Take conjugate 2 times. first treat root 2 and root 3 as a single term and do calculations. answer is (6*root2+4*root3-2*root30)/24

root3/4a2

If its volume is 64 cubic cm then its sides will be 4 cm

Write three rational numbers between root2 root3 ?

Because they cannot be expressed as ratios of integers.

It is known that the square root of an integer is either an integer or irrational. If we square root2 root3 we get 6. The square root of 6 is irrational. Therefore, root2 root3 is irrational.