4 x 58 = 232
58 x 34 = 1972 5/8 x 3/4 = 15/32
x = 6 So y = 9*6 + 4 = 54 + 4 = 58 The ordered pair is (6, 58)
16 x 58 = 928.
To solve for x: 2x2 + 10 = 58 2x2 = 48 x2 = 24 x = √24 x = √4 × √6 x = 2√6
4 x 58 = 232
4.7 x 58 4 x 58 = 232 .7 x 58 = 40.6 add these together and the answer is 272.6
The first ten positive integer multiples of 58 are: 1 x 58 = 58 2 x 58 = 116 3 x 58 = 174 4 x 58 = 232 5 x 58 = 290 6 x 58 = 348 7 x 58 = 406 8 x 58 = 464 9 x 58 = 522 10 x 58 = 580
58/75 = 58/75 x 100 % = 58 x 100/75 % = 58 x 4/3 % = 232/3 % ≈ 77.33 %
58 x 34 = 1972 5/8 x 3/4 = 15/32
1 x 232, 2 x 116, 4 x 58, 8 x 29, 29 x 8, 58 x 4, 116 x 2, 232 x 1.
1 x 116, 2 x 58, 4 x 29.
x = 6 So y = 9*6 + 4 = 54 + 4 = 58 The ordered pair is (6, 58)
The factors of 116 are 1, 2, 4, 29, 58, and 116. The prime factors of 116 are 2 x 2 x 29.The prime factors of 116 are 2 x 2 x 29.
58 x 58=3364 If you dont belive me check on a calculator
16 x 58 = 928.
To solve for x: 2x2 + 10 = 58 2x2 = 48 x2 = 24 x = √24 x = √4 × √6 x = 2√6