50 Meters in an Olympic Swimming Pool
The momentum of an object is given by the formula p = m*v, where m is mass and v is velocity. The average velocity of the skateboarder is 400m / 50s = 8 m/s. Therefore, the average momentum is 50 kg * 8 m/s = 400 kg m/s.
The acceleration of the car is 5 m/s^2. This is calculated by dividing the change in velocity (10 m/s - 5 m/s = 5 m/s) by the time taken for the velocity to change.
Distance is how far you go like the perimeter,or miles/kilometers.It is the amount of space or area you travel,or go.Example:You are standing in the middle of a field. Your house is 50 meters north of where you are.Draw a circle with radius 50 meters.Any place on that circle is a DISTANCE of 50 meters (magnitude= 50 meters, direction not important)If you decide to walk home, that is a DISPLACEMENT of 50 meters (Magnitude = 50 m, direction = NorthYou run in any direction and reach the circle in 50 seconds, that is a SPEED of 50 m/50s = 1 m/sYou run home and reach your house in 50 seconds, that is a VELOCITY of 50 m / 50 s = 1 m/s NorthYou start from a standing start. After 1 second you are running 0.75 m/s, after 2 s you are running 1.15 m/s your ACCELERATION is the change in VELOCITY divided by time.By Deena Dugdill12
A freely falling object, assuming no air friction, has an acceleration (a) equal to the gravitational constant, g (= 9.8 m/s2). Use this formula: v_final = v_initial + a * time_elapsed. Plug in appropriate values on the right-hand side. v_final = 0 + 9.8 [m/s2] * 10 [s] = 98 [m/s]. The closest answer would be 100 [m/s] ========================================
To find the acceleration, we first calculate the change in velocity: 4 m/s - 54 m/s = -50 m/s. Next, we use the formula for acceleration: acceleration = change in velocity / time = -50 m/s / 0.75 s = -66.67 m/s^2. The magnitude of the acceleration is 66.67 m/s^2.
The change in velocity is 85 m/s - 35 m/s = 50 m/s. Dividing this by the time in seconds gives an acceleration of 50 m/s / 20 s = 2.5 m/s^2. Using Newton's second law, F = ma, the force on the object is 148 kg * 2.5 m/s^2 = 370 N.
Meed velocity first. V = delta X/delta t V = 50 m/30 s = 1.666 m/s now, acceleration A = delta V/delta t A = 1.666 m/s/30 s = 0.056 m/s2 ============
5 m/s2 east
331.3 m/s.
The momentum of the bike can be calculated as mass times velocity, so the momentum of the bike is 50 kg * 10 m/s = 500 kg m/s. The momentum of the rider can be calculated as mass times velocity, so the momentum of the rider is 30 kg * 10 m/s = 300 kg m/s.
Example: Vertical velocity component of a 100 m/s cannonball fired at 30 degrees from horizontal = sin 30 * 100 = 50 m/s Find the maximum height reached. Take acceleration due to gravity at 10 (m/s)/s so: u = 50 m/s v = 0 a = - 10 m/s/s (approx) s = ? Using: v2 = u2 + ( 2 * a * s ) so: s = ( v2 - u2 ) / ( 2 * a ) s = ( 0 - 2500 ) / ( 2 * -10 ) s = 125 metres