255 = 51 x 5 so 51 is GCF
3/5 : 51 = (17 x 3 x 1), and 85 = (17 x 5 x 1). When you divide 51/85, the 17 and 1 cancel, so you have 3/5 simplest form.
Two examples: 255 ÷ 5 = 51 306 ÷ 6 = 51 Method: Times 51 by a number (51 x 5 = 255) : then divide 255 by answer (255 / 5 = 51).
1 x 255, 3 x 85, 5 x 51, 15 x 17, 17 x 15, 51 x 5, 85 x 3, 255 x 1
5 5 x 51 = 255 with a remainder of 48
The prime factors are: 2 x 5 = 10
765. 45 = 32 x 5 51 = 3 x 17 lcm = 32 x 5 x 17 = 765
255 = 51 x 5 so 51 is GCF
3/5 : 51 = (17 x 3 x 1), and 85 = (17 x 5 x 1). When you divide 51/85, the 17 and 1 cancel, so you have 3/5 simplest form.
Two examples: 255 ÷ 5 = 51 306 ÷ 6 = 51 Method: Times 51 by a number (51 x 5 = 255) : then divide 255 by answer (255 / 5 = 51).
1 x 255, 3 x 85, 5 x 51, 15 x 17, 17 x 15, 51 x 5, 85 x 3, 255 x 1
51 x 5 = 255
5 5 x 51 = 255 with a remainder of 48
51 = 3 x 1760 = 3 x 2 x 5 x 2GCF = 3
5 x 5 x 5 = 51+1+1 = 53 5 x 52 x 56 = 51+2+6 = 59 (5)3 = 51x3 = 53 (52)4 = 52x4 = 58
Multiply the integer with the denominator, add to the numerator, and put on top of the denominator. Example:10 1/5 = 51/5. The "51" was obtained as (10 x 5) + 1.Multiply the integer with the denominator, add to the numerator, and put on top of the denominator. Example:10 1/5 = 51/5. The "51" was obtained as (10 x 5) + 1.Multiply the integer with the denominator, add to the numerator, and put on top of the denominator. Example:10 1/5 = 51/5. The "51" was obtained as (10 x 5) + 1.Multiply the integer with the denominator, add to the numerator, and put on top of the denominator. Example:10 1/5 = 51/5. The "51" was obtained as (10 x 5) + 1.
9x+6=51 9x = 45 x= 5 9x-6=51 9x = 57 x= 6.33