Two examples:
255 ÷ 5 = 51
306 ÷ 6 = 51
Method: Times 51 by a number (51 x 5 = 255) : then divide 255 by answer (255 / 5 = 51).
15
yes because 51 divided by 3 equals 17.
There are 51 hundreds in 5105. This is because 5105 divided by 100 equals 51. In other words, 5105 can be broken down into 51 sets of 100.
9
39
153/3=51
12.75
5.6667
15
yes because 51 divided by 3 equals 17.
No. 51 divided by 4 equals 12 with a remainder of 3 or 12.75
17
2 goes into 102 51 times. (102 divided by 2 equals 51)
Yes, 153 divided by 3 equals 51.
17 3 times = 51
Applying the rules of BODMAS, 51 + (2/ -9) = 51 + (-0.2222....) = -51.2 recurring (that is, -51.22222...)
There are 51 hundreds in 5105. This is because 5105 divided by 100 equals 51. In other words, 5105 can be broken down into 51 sets of 100.