55 x 6 = 330
6 is three times 2 so the answer is three times 55 which is 165
7 can go into 55 a total of 7 times, as 7 multiplied by 7 equals 49, which is the largest multiple of 7 that is less than 55. When you subtract 49 from 55, you have a remainder of 6. Thus, 7 fits into 55 seven times with a remainder of 6.
55/6 = 9.16 recurring (that is, 9.16666...)
Six can go into 55 a total of 9 times, since 6 multiplied by 9 equals 54, which is the largest multiple of 6 that is less than or equal to 55. After 9 times, there is a remainder of 1, as 55 minus 54 equals 1. Therefore, the answer is 9 times with a remainder of 1.
9 times with a remainder of 1
6 X 55 = 330
6 is three times 2 so the answer is three times 55 which is 165
55 ÷ 6 = 9 with remainder 1 or 9.1667
No the correct answer is 54. 5x11 55
55 times 6 = 330
7 can go into 55 a total of 7 times, as 7 multiplied by 7 equals 49, which is the largest multiple of 7 that is less than 55. When you subtract 49 from 55, you have a remainder of 6. Thus, 7 fits into 55 seven times with a remainder of 6.
9 with 1 remaining 55 - 1 = 54 = 6 x 9
55
55 times with a remainder of 5
Well, honey, 8 can go into 55 a total of 6 times with a remainder of 7. So, technically, 8 goes into 55 6 times evenly, but there's always a little leftover party of 7 that just can't be divided up. Math can be a real party pooper sometimes, can't it?
55/6 = 9.16 recurring (that is, 9.16666...)
The pattern appears to be that 2 is 27 times smaller than 55, so following the same logic, 6 would be 27 times smaller than the missing value. Therefore, 6 is to 162 as 2 is to 55.