9 with 1 remaining
55 - 1 = 54 = 6 x 9
55 ÷ 6 = 9 with remainder 1 or 9.1667
55
55 times with a remainder of 5
Oh, dude, let me break it down for you. So, 8 can go into 55 about 6 times with a remainder of 7. It's like when you're trying to split a pizza with your friends, but there's always that one slice left over. So yeah, 8 goes into 55 six times, but there's a little leftover slice hanging out.
Well, isn't that a happy little math question! If you take 55 and divide it by 7, you'll find that 7 goes into 55 a total of 7 times. Just imagine those little sevens dancing around and fitting perfectly into 55, creating a lovely little mathematical masterpiece.
55 ÷ 6 = 9 with remainder 1 or 9.1667
55
55 times with a remainder of 5
7 times with 6 remaining
6 R 1
9 times with a remainder of 1
55/6 = 9.16 recurring (that is, 9.16666...)
6, remainder 1
7 can go into 55 a total of 7 times, as 7 multiplied by 7 equals 49, which is the largest multiple of 7 that is less than 55. When you subtract 49 from 55, you have a remainder of 6. Thus, 7 fits into 55 seven times with a remainder of 6.
Six can go into 55 a total of 9 times, since 6 multiplied by 9 equals 54, which is the largest multiple of 6 that is less than or equal to 55. After 9 times, there is a remainder of 1, as 55 minus 54 equals 1. Therefore, the answer is 9 times with a remainder of 1.
To find out how many 8s go into 55, you can perform the division (55 \div 8), which equals 6.875. This means that 8 goes into 55 a total of 6 full times, with some remainder left over. Therefore, there are 6 complete 8s in 55.
Oh, dude, let me break it down for you. So, 8 can go into 55 about 6 times with a remainder of 7. It's like when you're trying to split a pizza with your friends, but there's always that one slice left over. So yeah, 8 goes into 55 six times, but there's a little leftover slice hanging out.