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The rules as we now know them today governing the Roman numeral system had absolutely nothing to with the ancient Romans whatsoever because they were introduced during the Middle Ages and so as a result nowadays 599 and 219 are now considered to be DXCIX and CCXIX in Roman numerals which hardly lends themselves quite easily towards arithmetical operations but there exist historical evidence to suggest that the ancient Romans would have worked out the above calculations as in the following four formats:-

IDC+ICCXX = DCCCXVIII => (600-1)+(220-1) = 818

DLXXXXVIIII+CCXVIIII = DCCCXVIII => 599+219 = 818

IDC-ICCXX = CCCLXXX => (600-1)-(220-1) = 380

DLXXXXVIIII-CCXVIIII = CCCLXXX => 599-219 = 380

The above calculations were fairly simple and straightforward to work out but for more complicated calculations the Romans would have made use of an abacus calculating device.

QED

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Q: What is 599 plus 219 added in two different ways and 599 minus 219 subtracted in two different ways but working out all four calculations in Roman numerals with explanations?
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How would you actually add together 1666 and 1999 in two different ways entirely in Roman numerals throughout both calculations with explanations?

See answer to question: ' How do you add together 1666 and 1999 in two different ways using Roman numerals'


What is 1776 plus 444 added in two different ways and 17776 minus 444 subtracted in two different ways but working out all four calculations in Roman numerals?

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How would you work out 1776 plus 549 in two different ways and 1776 minus 549 in two different ways but working out all four calculations entirely in Roman numerals with explanations?

Roman numerals are entirely inappropriate for doing such calculations. I believe the people in Roman times did such calculations on an abacus or something similar - which is basically similar to converting them to the Arabic numbers we use. If you really want to do it in Roman numerals - which is basically NOT a good idea - you would have to keep the thousands, hundreds, etc. separate, and handle carry (for addition) and borrowing (for subtraction).


What is 1776 plus 249 added in two different ways and 1776 minus 249 subtracted in two different ways but working out all four calculations in Roman numerals with work shown?

Nowadays 249 when converted into Roman numerals is now considered to be CCXLIX but the ancient Romans probably worked out the required calculations as follows:-MDCCLXXVI+ICCL = MMXXV => 1776+(250-1) = 2025MDCCLXXVI+CCXXXXVIIII = MMXXV => 1776+249 = 2025MDCCLXXVI-ICCL = MDXXVII => 1776-(250-1) = 1527MDCCLXXVI-CCXXXXVIIII = MDXXVII => 1776-249 = 1527For more complicated calculations the Romans would have made use of an abacus calculating device.QED


What is 1999 plus 666 added in two different ways and 1999 minus 666 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?

The rules as we know them today now governing the Roman numeral system had absolutely nothing to do with the Romans because they were introduced during the Middle Ages and as a result of these rules the equivalent of 1999 when converted into Roman numerals is now considered to be MCMXCIX which hardly lends itself quite easily for the purpose of mathematical operations but notwithstanding the aforementioned inasmuch that there exist credible evidence to support the premiss that the ancient Romans would have carried out the requested calculations as in the following formats:-MDCCCCLXXXXVIIII+DCLXVI = MMDCLXV => 1999+666 = 2665IMM+DCLXVI = MMDCLXV => (2000-1)+666 = 2665MDCCCCLXXXXVIIII-DCLXVI = MCCCXXXIII => 1999-666 = 1333IMM-DCLXVI is the same as the above because IMM = MDCCCCLXXXXVIIIIFor more intricate and complicated calculations the Romans would have made use of an abacus calculating device.QED by David Gambell

Related questions

How would you actually add together 1666 and 1999 in two different ways entirely in Roman numerals throughout both calculations with explanations?

See answer to question: ' How do you add together 1666 and 1999 in two different ways using Roman numerals'


What is 1776 plus 444 added in two different ways and 17776 minus 444 subtracted in two different ways but working out all four calculations in Roman numerals?

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How would you work out 1776 plus 549 in two different ways and 1776 minus 549 in two different ways but working out all four calculations entirely in Roman numerals with explanations?

Roman numerals are entirely inappropriate for doing such calculations. I believe the people in Roman times did such calculations on an abacus or something similar - which is basically similar to converting them to the Arabic numbers we use. If you really want to do it in Roman numerals - which is basically NOT a good idea - you would have to keep the thousands, hundreds, etc. separate, and handle carry (for addition) and borrowing (for subtraction).


How would you work out 19 plus 9 in four different ways and 19 minus 9 in four different ways but calculating all eight calculations completely in Roman numerals from start to finish with explanations?

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What is 1776 plus 249 added in two different ways and 1776 minus 249 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?

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What is 1776 plus 249 added in two different ways and 1776 minus 249 subtracted in two different ways but working out all four calculations in Roman numerals with work shown?

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What is 1999 plus 666 added in two different ways and 1999 minus 666 subtracted in two different ways but working out all four calculations entirely in Roman numerals with explanations?

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