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A plus b plus c equals 180 b-3a and c equals 5a what the answer to c?
From your description, I get: a + b + c = 180b - 3a c = 5a You have two equations and three unknowns, which is unsolvable.
A plus b plus c equals 180 b equals 3a c equals 5a?
a = 20 b = 60 c = 100
In triangle ABC angle B is 5 times angle A and angle C is 8 less than 4 times angle A what is the size of angle A?
B = 5A C = 4A - 8 The sum of the angles of a triangle = 180° A + B + C = 180 A + 5A + (4A - 8) = 180 10A = 188 A = 18.8° (and therefore B = 94° and C = 67.2°)
How do you solve similtaneously -5a plus b equals 2 and -a -5b equals 0?
-5a + b = 2 AND -a - 5b = 0 -5a + b = 2 b = 2 + 5a *using above -a - 5b = 0 -a - 5(2 + 5a) = 0 -a - 10 - 25a = 0 -26a = 10 a = 10/-26 *using 'a' value 5a + b = 2 5(10/-26) + b = 2 -25/13 -2 = -b b = 51/13 Therefore a = 10/-26 b = 51/13
What is b squared plus 5a plus 6 divided by b squared minus 2?
It simplifies to 5a+4 !
What is the answer to a plus b plus c equals 180 b equals 3a c equals 5a?
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
A plus b plus c equals 180 b-3a and c equals 5a what the answer to c?
From your description, I get: a + b + c = 180b - 3a c = 5a You have two equations and three unknowns, which is unsolvable.
A plus b plus c equals 180 b equals 3a c equals 5a?
a = 20 b = 60 c = 100
What is 4a plus 3c-2b-c plus a-b?
4a + 3c - 2b - c + a - b = 5a - 3b + 2c
Ina triangle ABC angle B is 4 times angle A and angle C is 11 degrease less than 5 times angle A find the size of the angles?
Angle A = A Angle B = 4A Angle C = 5A-11 Sum of angles in a triangle is 180o. 180 = A + B + C = A + 4A + 5A-11 = 10A - 11 10A = 191 A = 19.1o B = 4A = 76.4o C = 5A-11 = 84.5o
In triangle ABC angle B is 5 times angle A and angle C is 8 less than 4 times angle A what is the size of angle A?
B = 5A C = 4A - 8 The sum of the angles of a triangle = 180° A + B + C = 180 A + 5A + (4A - 8) = 180 10A = 188 A = 18.8° (and therefore B = 94° and C = 67.2°)
How do you factorise 10a-5ab?
15
In a triangle abc angle b is 4 times angle a and angle c is 9 degrees less than 5 times angle a the size of a is?
a = a b = 4a c = 5a-9 a+4a+5a-9 = 180 10a = 189 a = 18.9 degrees
How do you solve similtaneously -5a plus b equals 2 and -a -5b equals 0?
-5a + b = 2 AND -a - 5b = 0 -5a + b = 2 b = 2 + 5a *using above -a - 5b = 0 -a - 5(2 + 5a) = 0 -a - 10 - 25a = 0 -26a = 10 a = 10/-26 *using 'a' value 5a + b = 2 5(10/-26) + b = 2 -25/13 -2 = -b b = 51/13 Therefore a = 10/-26 b = 51/13
What is 3a plus 2b-4a plus b?
The given expression can be simplified to: 3b-a
What is b squared plus 5a plus 6 divided by b squared minus 2?
It simplifies to 5a+4 !
What is 16a plus 3b-c-5a plus 3b plus 7c plus a equals?
12a + 6b + 6c = 6(2a + b + c)
