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From your description, I get: a + b + c = 180b - 3a c = 5a You have two equations and three unknowns, which is unsolvable.
a = 20 b = 60 c = 100
B = 5A C = 4A - 8 The sum of the angles of a triangle = 180° A + B + C = 180 A + 5A + (4A - 8) = 180 10A = 188 A = 18.8° (and therefore B = 94° and C = 67.2°)
-5a + b = 2 AND -a - 5b = 0 -5a + b = 2 b = 2 + 5a *using above -a - 5b = 0 -a - 5(2 + 5a) = 0 -a - 10 - 25a = 0 -26a = 10 a = 10/-26 *using 'a' value 5a + b = 2 5(10/-26) + b = 2 -25/13 -2 = -b b = 51/13 Therefore a = 10/-26 b = 51/13
It simplifies to 5a+4 !