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Can x squared plus 25 be factored?
Not in real numbers. It can be factored to (x - 5i)(x + 5i) where i is the square root of negative one.
What is the complex conjugate -6-5i?
6+5i
What is the conjugate of 7-5i?
12
How do you solve 2 divided by 5i?
0.4
What are the cube roots of 1000i?
5√3 + 5i, -5√3 + 5i, -10i
How do you factor x squared plus 25?
(x-5i)(x+5i)
Can x squared plus 25 be factored?
Not in real numbers. It can be factored to (x - 5i)(x + 5i) where i is the square root of negative one.
How do you factor 9x squared plus 25?
9x2 + 25 has no rational factors. Its factorisation in the complex domain is:(3x + 5i)*(3x - 5i) where i is the imaginary square root of -1.
What is the reciprocal of 3 plus 5i?
1/(3+5i)=(3-5i)/((3+5i)(3-5i))=(3-5i)/(9+25)=(3-5i)/34
What are 10 complex numbers with the absolute value of 5?
Use the Pythagorean theorem. 5, -5, 5i, and -5i will work, as well as any combination of a real and imaginary number such that (real part) squared + (imaginary part) squared = 25, for example, 4 + 3i, 3 + 4i, 4 - 3i, etc.
Complex conjugate of 5i?
0 + 5i Its complex conjugate is 0 - 5i
What is 1 divided by 2 plus 5i in the form a plus bi?
1/(2 + 5i) (multiply both the numerator and the denominator by 2 - 5i)= 1(2 - 5i)/(2 + 5i)(2 - 5i)= (2 - 5i)/(4 - 25i2) (substitute -1 for i2)= (2 - 5i)/(4 + 25)= (2 - 5i)/29= 2/29 - (5/29)i
What is the absolute value of -2-5i?
You can get the absolute value of a complex number by using Pythagoras's Theorem, which in this case is: absolute value (i.e., distance from zero) = the square root of (real part squared + imaginary part squared).
Solve x squared equals -25?
x2 = -25 There exists no real number for which this is true, so we must use imaginary numbers... x = 5i
What is the complex conjugate -6-5i?
6+5i
What is the conjugate of 7-5i?
12
What is the conjugate of 11 plus 5i?
To find the complex conjugate change the sign of the imaginary part: For 11 + 5i the complex conjugate is 11 - 5i.
