nCr = (n!)/(r!(n-r)!) and the answer is 15
6c2 -11c + 3 factors are (3c - 1)(2c - 3)
products- 6C2+6H2O reactants- C6H12O6+6O2
What is The simplified form of (3a2 - 5ab plus c2) plus (-2a2 plus 10ab plus 6c2)
products- 6C2+6H2O reactants- C6H12O6+6O2
C12h22o11 ---> 6c2 + 11h20
(12c5 - 18c3 + 9c) / (-3c) = -4c4 + 6c2 - 3
y=mc2 + D-72 subdivide the 6 into the M hereforoe u get: y=6c2+D-72 = 175 I am a monash professor and this is a correct answer.
There are 6C2 = 6*5/(2*1) = 15 pairs.
the answer is 15 not 21....because the total no. of handshakes will be (5+4+3+2+1) not (6+5+4+3+2+1) as the 1st person will have only 5options 2nd will have 4 options n so on...also we can calculate the answer by combination..that is 6C2.
To determine the number of pairs for 6 nodes using a formula, you can use combination formula. In this case, the formula would be nC2, where n represents the number of nodes. Substituting n=6, the formula becomes 6C2, which is equal to 15. Therefore, there would be 15 pairs of nodes for 6 total nodes.
The answer depends on whether the children are picked at random. If they were selected from inside a girls' school the probability should be quite close to 0. Likewise, if the children were picked inside a boys' school. If six children are picked at random from a large group of children with an equal number of boys and girls, then the answer is 6C2*(1/2)6 = 15/32 = 0.47, approx.
When you factor, you take a common polynomial and multiply it by another polynomial (both with the same variable [i.e. both having "y"]) which when solved would create the polynomial in the problem.1) -p2+8p-12-(p-6)(p-2)2) 2y2+15y+7(y+7)(2y+1)3) 6c2+7c+2(2c+1)(3c+2)4) -2b2-5b+12-(b+4)(2b-3)