6c2 -11c + 3 factors are (3c - 1)(2c - 3)
products- 6C2+6H2O reactants- C6H12O6+6O2
What is The simplified form of (3a2 - 5ab plus c2) plus (-2a2 plus 10ab plus 6c2)
products- 6C2+6H2O reactants- C6H12O6+6O2
(12c5 - 18c3 + 9c) / (-3c) = -4c4 + 6c2 - 3
y=mc2 + D-72 subdivide the 6 into the M hereforoe u get: y=6c2+D-72 = 175 I am a monash professor and this is a correct answer.
There are 6C2 = 6*5/(2*1) = 15 pairs.
The balanced equation for the breakdown of sugar (sucrose) into carbon and water when heated is: C12H22O11 -> 12C + 11H2O. This is a combustion reaction that occurs when sugar is heated in the presence of oxygen, producing carbon (C) and water (H2O) as the products.
the answer is 15 not 21....because the total no. of handshakes will be (5+4+3+2+1) not (6+5+4+3+2+1) as the 1st person will have only 5options 2nd will have 4 options n so on...also we can calculate the answer by combination..that is 6C2.
To determine the number of pairs for 6 nodes using a formula, you can use combination formula. In this case, the formula would be nC2, where n represents the number of nodes. Substituting n=6, the formula becomes 6C2, which is equal to 15. Therefore, there would be 15 pairs of nodes for 6 total nodes.
The answer depends on whether the children are picked at random. If they were selected from inside a girls' school the probability should be quite close to 0. Likewise, if the children were picked inside a boys' school. If six children are picked at random from a large group of children with an equal number of boys and girls, then the answer is 6C2*(1/2)6 = 15/32 = 0.47, approx.
When you factor, you take a common polynomial and multiply it by another polynomial (both with the same variable [i.e. both having "y"]) which when solved would create the polynomial in the problem.1) -p2+8p-12-(p-6)(p-2)2) 2y2+15y+7(y+7)(2y+1)3) 6c2+7c+2(2c+1)(3c+2)4) -2b2-5b+12-(b+4)(2b-3)