6 divided 9 as frac = 0.6666666666666666
Half divided by 3 is calculated as ( \frac{1/2}{3} ), which can be simplified to ( \frac{1}{2} \times \frac{1}{3} = \frac{1}{6} ). Therefore, half divided by 3 equals ( \frac{1}{6} ).
One sixth divided by one twelfth is calculated by multiplying one sixth by the reciprocal of one twelfth. This can be expressed as ( \frac{1}{6} \div \frac{1}{12} = \frac{1}{6} \times \frac{12}{1} = \frac{12}{6} = 2 ). Therefore, one sixth divided by one twelfth equals 2.
To add ( \frac{5}{6} ) and ( \frac{3}{8} ), you first need a common denominator. The least common multiple of 6 and 8 is 24. Converting ( \frac{5}{6} ) to a fraction with a denominator of 24 gives ( \frac{20}{24} ), and converting ( \frac{3}{8} ) gives ( \frac{9}{24} ). Adding these together results in ( \frac{20}{24} + \frac{9}{24} = \frac{29}{24} ), which can also be expressed as ( 1 \frac{5}{24} ).
To express the sum of the given terms, we write it as (\frac{9}{y} + 4 + \frac{6}{y} - 3). Combining the constant terms gives us (4 - 3 = 1). Therefore, the expression simplifies to (\frac{9}{y} + \frac{6}{y} + 1 = \frac{15}{y} + 1).
To convert the fraction ( \frac{15}{9} ) to a proper fraction, you can simplify it. First, divide both the numerator and the denominator by their greatest common divisor, which is 3. This gives you ( \frac{5}{3} ), which is still an improper fraction. To express it as a proper fraction, you can represent it as ( 1 \frac{2}{3} ) (one whole and two-thirds). To address the "over 6" part, you could express ( \frac{15}{9} ) in terms of a denominator of 6 by finding an equivalent fraction: ( \frac{15}{9} = \frac{10}{6} ) after simplification. However, this is still improper; as a mixed number, it would be ( 1 \frac{2}{6} ) or simplified further to ( 1 \frac{1}{3} ).
To find the number of different groups of 6 that can be formed from 9, you can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 9 ) and ( r = 6 ). Thus, ( C(9, 6) = \frac{9!}{6! \cdot 3!} = \frac{9 \times 8 \times 7}{3 \times 2 \times 1} = 84 ). Therefore, there are 84 different groups of 6 from a set of 9.
To find the fraction of pizza that was uneaten, we first add the fractions eaten by each workman: ( \frac{1}{3} + \frac{1}{4} + \frac{1}{6} ). The least common multiple of 3, 4, and 6 is 12, so we convert the fractions: ( \frac{4}{12} + \frac{3}{12} + \frac{2}{12} = \frac{9}{12} ). Therefore, the fraction of pizza that was uneaten is ( 1 - \frac{9}{12} = \frac{3}{12} ), which simplifies to ( \frac{1}{4} ).
To solve the proportion 9 is to 2 as x is to 6, we can set up the equation ( \frac{9}{2} = \frac{x}{6} ). Cross-multiplying gives us ( 9 \times 6 = 2 \times x ), or ( 54 = 2x ). Dividing both sides by 2, we find that ( x = 27 ). Therefore, the answer is ( x = 27 ).
If you mean **(\frac{1}{4} + 6 \frac{1}{2} \times 1)**, let's break it down: Convert **mixed number** (6 \frac{1}{2}) into an improper fraction: [ 6 \frac{1}{2} = \frac{13}{2} ] Multiply by **1** (which doesn’t change the value): [ \frac{13}{2} \times 1 = \frac{13}{2} ] Add (\frac{1}{4}): [ \frac{1}{4} + \frac{13}{2} ] Find a **common denominator** (LCM of 4 and 2 is **4**): [ \frac{13}{2} = \frac{26}{4} ] Perform the addition: [ \frac{1}{4} + \frac{26}{4} = \frac{27}{4} ] Convert to a **mixed number**: [ \frac{27}{4} = 6 \frac{3}{4} ] **Final Answer:** [ 6 \frac{3}{4} \text{ or } 6.75 ]
9 divided by 6 is 1.5
48 divided by 6 plus 9 is 17.
The quotient of 54 divided by 9 is 6. In division, the dividend (54) is divided by the divisor (9) to give the quotient (6). This means that 54 can be evenly divided into 9 groups of 6.