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What is 6 divided 9 as frac?

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Anonymous

10y ago
Updated: 7/26/2021

6 divided 9 as frac = 0.6666666666666666

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Noble Bogan

Lvl 10
4y ago

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Related Questions

Can 6 9 be simplified?

Yes, the fraction ( \frac{6}{9} ) can be simplified. Both the numerator and the denominator can be divided by their greatest common divisor, which is 3. Therefore, ( \frac{6}{9} ) simplifies to ( \frac{2}{3} ).


What is half divided by 3?

Half divided by 3 is calculated as ( \frac{1/2}{3} ), which can be simplified to ( \frac{1}{2} \times \frac{1}{3} = \frac{1}{6} ). Therefore, half divided by 3 equals ( \frac{1}{6} ).


What is 9 12th's plus 2 fourths?

To add ( \frac{9}{12} ) and ( \frac{2}{4} ), first simplify ( \frac{2}{4} ) to ( \frac{1}{2} ) or ( \frac{6}{12} ) for a common denominator. Now, ( \frac{9}{12} + \frac{6}{12} = \frac{15}{12} ). This can be simplified to ( \frac{5}{4} ) or ( 1 \frac{1}{4} ).


What is one sixth divided by one twelfth?

One sixth divided by one twelfth is calculated by multiplying one sixth by the reciprocal of one twelfth. This can be expressed as ( \frac{1}{6} \div \frac{1}{12} = \frac{1}{6} \times \frac{12}{1} = \frac{12}{6} = 2 ). Therefore, one sixth divided by one twelfth equals 2.


What is one and one half plus one sixth?

One and one half can be expressed as ( \frac{3}{2} ). To add one sixth (( \frac{1}{6} )), we need a common denominator, which is 6. Converting ( \frac{3}{2} ) to sixths gives us ( \frac{9}{6} ). Therefore, ( \frac{9}{6} + \frac{1}{6} = \frac{10}{6} ), which simplifies to ( \frac{5}{3} ) or one and two thirds.


What is two and a half divided by two and two fourths?

To divide two and a half (2.5) by two and two fourths (2.5), first convert both numbers to improper fractions. Two and a half is ( \frac{5}{2} ) and two and two fourths simplifies to ( \frac{9}{4} ). Dividing these gives ( \frac{5}{2} \div \frac{9}{4} = \frac{5}{2} \times \frac{4}{9} = \frac{20}{18} = \frac{10}{9} ). Thus, two and a half divided by two and two fourths equals ( \frac{10}{9} ) or approximately 1.11.


What is a proportion that has means 6 and 18 and extremes 9 and 12?

In a proportion, the means are the middle terms, and the extremes are the outer terms. Given the means are 6 and 18, and the extremes are 9 and 12, the proportion can be expressed as ( \frac{9}{12} = \frac{6}{18} ). Simplifying both sides, ( \frac{9}{12} ) reduces to ( \frac{3}{4} ), and ( \frac{6}{18} ) reduces to ( \frac{1}{3} ), indicating that these values do not form a valid proportion.


Is 6 over 1 3rds irrational?

To determine if (6) over (1 \frac{1}{3}) is irrational, first convert (1 \frac{1}{3}) to an improper fraction, which is (\frac{4}{3}). Then, calculate (6 \div \frac{4}{3}), which is the same as multiplying (6) by the reciprocal of (\frac{4}{3}), resulting in (6 \times \frac{3}{4} = \frac{18}{4} = \frac{9}{2}). Since (\frac{9}{2}) is a rational number, (6) over (1 \frac{1}{3}) is not irrational.


What is 1 sixth plus 3 eighths?

To add ( \frac{1}{6} ) and ( \frac{3}{8} ), we first find a common denominator, which is 24. Converting the fractions, ( \frac{1}{6} ) becomes ( \frac{4}{24} ) and ( \frac{3}{8} ) becomes ( \frac{9}{24} ). Adding these gives ( \frac{4}{24} + \frac{9}{24} = \frac{13}{24} ). Thus, ( \frac{1}{6} + \frac{3}{8} = \frac{13}{24} ).


What is the sum of 9 divide y plus 4 plus 6 divide y-3?

To express the sum of the given terms, we write it as (\frac{9}{y} + 4 + \frac{6}{y} - 3). Combining the constant terms gives us (4 - 3 = 1). Therefore, the expression simplifies to (\frac{9}{y} + \frac{6}{y} + 1 = \frac{15}{y} + 1).


What is 5 6 plus three eighths?

To add ( \frac{5}{6} ) and ( \frac{3}{8} ), you first need a common denominator. The least common multiple of 6 and 8 is 24. Converting ( \frac{5}{6} ) to a fraction with a denominator of 24 gives ( \frac{20}{24} ), and converting ( \frac{3}{8} ) gives ( \frac{9}{24} ). Adding these together results in ( \frac{20}{24} + \frac{9}{24} = \frac{29}{24} ), which can also be expressed as ( 1 \frac{5}{24} ).


What is the fractions equivalent to 2 over 3?

Fractions equivalent to ( \frac{2}{3} ) can be found by multiplying both the numerator and denominator by the same non-zero integer. For example, multiplying by 2 gives ( \frac{4}{6} ), and multiplying by 3 gives ( \frac{6}{9} ). Thus, ( \frac{4}{6} ) and ( \frac{6}{9} ) are both equivalent to ( \frac{2}{3} ).