6 divided 9 as frac = 0.6666666666666666
Yes, the fraction ( \frac{6}{9} ) can be simplified. Both the numerator and the denominator can be divided by their greatest common divisor, which is 3. Therefore, ( \frac{6}{9} ) simplifies to ( \frac{2}{3} ).
Half divided by 3 is calculated as ( \frac{1/2}{3} ), which can be simplified to ( \frac{1}{2} \times \frac{1}{3} = \frac{1}{6} ). Therefore, half divided by 3 equals ( \frac{1}{6} ).
To add ( \frac{9}{12} ) and ( \frac{2}{4} ), first simplify ( \frac{2}{4} ) to ( \frac{1}{2} ) or ( \frac{6}{12} ) for a common denominator. Now, ( \frac{9}{12} + \frac{6}{12} = \frac{15}{12} ). This can be simplified to ( \frac{5}{4} ) or ( 1 \frac{1}{4} ).
One sixth divided by one twelfth is calculated by multiplying one sixth by the reciprocal of one twelfth. This can be expressed as ( \frac{1}{6} \div \frac{1}{12} = \frac{1}{6} \times \frac{12}{1} = \frac{12}{6} = 2 ). Therefore, one sixth divided by one twelfth equals 2.
One and one half can be expressed as ( \frac{3}{2} ). To add one sixth (( \frac{1}{6} )), we need a common denominator, which is 6. Converting ( \frac{3}{2} ) to sixths gives us ( \frac{9}{6} ). Therefore, ( \frac{9}{6} + \frac{1}{6} = \frac{10}{6} ), which simplifies to ( \frac{5}{3} ) or one and two thirds.
To divide two and a half (2.5) by two and two fourths (2.5), first convert both numbers to improper fractions. Two and a half is ( \frac{5}{2} ) and two and two fourths simplifies to ( \frac{9}{4} ). Dividing these gives ( \frac{5}{2} \div \frac{9}{4} = \frac{5}{2} \times \frac{4}{9} = \frac{20}{18} = \frac{10}{9} ). Thus, two and a half divided by two and two fourths equals ( \frac{10}{9} ) or approximately 1.11.
In a proportion, the means are the middle terms, and the extremes are the outer terms. Given the means are 6 and 18, and the extremes are 9 and 12, the proportion can be expressed as ( \frac{9}{12} = \frac{6}{18} ). Simplifying both sides, ( \frac{9}{12} ) reduces to ( \frac{3}{4} ), and ( \frac{6}{18} ) reduces to ( \frac{1}{3} ), indicating that these values do not form a valid proportion.
To determine if (6) over (1 \frac{1}{3}) is irrational, first convert (1 \frac{1}{3}) to an improper fraction, which is (\frac{4}{3}). Then, calculate (6 \div \frac{4}{3}), which is the same as multiplying (6) by the reciprocal of (\frac{4}{3}), resulting in (6 \times \frac{3}{4} = \frac{18}{4} = \frac{9}{2}). Since (\frac{9}{2}) is a rational number, (6) over (1 \frac{1}{3}) is not irrational.
To add ( \frac{1}{6} ) and ( \frac{3}{8} ), we first find a common denominator, which is 24. Converting the fractions, ( \frac{1}{6} ) becomes ( \frac{4}{24} ) and ( \frac{3}{8} ) becomes ( \frac{9}{24} ). Adding these gives ( \frac{4}{24} + \frac{9}{24} = \frac{13}{24} ). Thus, ( \frac{1}{6} + \frac{3}{8} = \frac{13}{24} ).
To express the sum of the given terms, we write it as (\frac{9}{y} + 4 + \frac{6}{y} - 3). Combining the constant terms gives us (4 - 3 = 1). Therefore, the expression simplifies to (\frac{9}{y} + \frac{6}{y} + 1 = \frac{15}{y} + 1).
To add ( \frac{5}{6} ) and ( \frac{3}{8} ), you first need a common denominator. The least common multiple of 6 and 8 is 24. Converting ( \frac{5}{6} ) to a fraction with a denominator of 24 gives ( \frac{20}{24} ), and converting ( \frac{3}{8} ) gives ( \frac{9}{24} ). Adding these together results in ( \frac{20}{24} + \frac{9}{24} = \frac{29}{24} ), which can also be expressed as ( 1 \frac{5}{24} ).
Fractions equivalent to ( \frac{2}{3} ) can be found by multiplying both the numerator and denominator by the same non-zero integer. For example, multiplying by 2 gives ( \frac{4}{6} ), and multiplying by 3 gives ( \frac{6}{9} ). Thus, ( \frac{4}{6} ) and ( \frac{6}{9} ) are both equivalent to ( \frac{2}{3} ).