6p divide by 3p = 2
-9p + 6p = -3p
First get all the p variables on one side of the equation by subtracting 6p from both sides. Giving you 3p + 14 = 23 Now subtract 14 from both sides. 3p = 9 Finally divide both sides by 3. p = 3
None because without an equality sign it is not an equation but it can be simplified to 3p^2 +6p
If your question is about 6p = 108, then here's how you do it. # Divide both sides by 6, so the variable p is by itself. 6p/6 = p, and 108/6 = 18 So, in the above equation, p = 18.
8-3p-4 = 2p 4 - 3p = 2p add 3p to both sides 4 = 5p divide both sides by 5 4/5 = p
3p + 6p = (3 + 6)p = 9p
3p
If: 6p-2-3p = 16 Then: p = 6
-9p + 6p = -3p
6p/4 equivalent to = 3p/2
The length of BAC in a circle P where BC is 24ft is 3p and not 6p 12p or 24p.
First get all the p variables on one side of the equation by subtracting 6p from both sides. Giving you 3p + 14 = 23 Now subtract 14 from both sides. 3p = 9 Finally divide both sides by 3. p = 3
None because without an equality sign it is not an equation but it can be simplified to 3p^2 +6p
3pq - 6p2 = 3p*(q - 2p)
answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}
If your question is about 6p = 108, then here's how you do it. # Divide both sides by 6, so the variable p is by itself. 6p/6 = p, and 108/6 = 18 So, in the above equation, p = 18.
1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p