3p + 6p = (3 + 6)p = 9p
3p
3p
If: 6p-2-3p = 16 Then: p = 6
9
-9p + 6p = -3p
6p/4 equivalent to = 3p/2
The length of BAC in a circle P where BC is 24ft is 3p and not 6p 12p or 24p.
First get all the p variables on one side of the equation by subtracting 6p from both sides. Giving you 3p + 14 = 23 Now subtract 14 from both sides. 3p = 9 Finally divide both sides by 3. p = 3
3pq - 6p2 = 3p*(q - 2p)
None because without an equality sign it is not an equation but it can be simplified to 3p^2 +6p
answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}