1 and 7.
The answer is 7s + 49.
Puto
The equivalent is 7s+2s = 9s
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5.28751 7s equals 37.
There is one 7s orbital with two sub-orbitals: 7s(+1/2) and 7s(-1/2) . A picture of this 7s orbital is in 'Related links'
nothing
Expressed algebraically, this would equal 7s - 5.
8 / 7 in long division is however many 7s go into 8. so there's 1x 7 in 8 with 1 remainder. For this example, assume every number beyond is a 10, multiplied by the remainder. so, it'd be 7s into 10, which is 1 again. Then 7s into 30, which is 4. Then 7s into 20, which is 2. Then 7s into 60, which 8. Then 7s into 40, which is 5. Then 7s into 50, which is 7. And this is a reoccuring number, making it 1.142857142857 and so on.
You said that 4(2s - 1) = 7s + 12Eliminate parentheses: 8s - 4 = 7s + 12Add 4 to each side: 8s = 7s + 16Subtract 7s from each side: s = 16
7s + 12 = 131 Therefore, 7s = 119 s = 119/7 Therefore, s = 17
To find how many 7s are in 93, you can divide 93 by 7. When you do this calculation, 93 ÷ 7 equals approximately 13.29. This means there are 13 full 7s in 93, with a remainder.