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Q: What is 7p plus 2 equals 5p plus 8?

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7p+5q=-3, p=1 7Xp+5q=-3 7+5q=-3 5p=-10 p=-2

4p+9-7p+2 -3p+11 p = 11/3

4p + 9 - 7p + 2 4p - 7p + 9 + 2 p(4 - 7) + 9 + 2 -3p + 11

11p+11

7p + 2q = 46 . . . . (A) 5p + 3q = 36 . . . . (B) 3*(A): 21p + 6q = 138 2*(B): 10p + 6q = 72 Subtracting gives 11p = 66 so that p = 6 Substitute for p in (A): 7*6 + 2q = 46 or 42 + 2q = 46 which gives 2q = 4 so that q = 2 Solution: (p, q) = (6,2)

4p + 9 + (-7p) + 2 = 4p - 7p + 9 + 2 = -3p + 11

3p + 4p +10 = 5p + 2 Subtracting 5p from both sides: 3p + 4p - 5p + 10 = 5p + 2 - 5p ie 2p + 10 = 2 Subtract 10 from both sides: 2p + 10 - 10 = 2 - 10 ie 2p = -8 Divide both sides by 2: p = -4

2p2-5p+2 = 0 (2p-1)(p-2) = 0 p = 1/2 and p = 2

15 = 5 +( 9p - 4p) 15 = 5 + 5p 15 - 5= 5 -5 +5p 10 = 5p there for p = 10/5 = 2

7p+2 is an algebraic expression. Since it is neither an equation nor an equality, it cannot have a solution or answer.

Collect like terms together: 4p + 9 + 7p + 2 = (4p + 7p) + (9 + 2) = (4 + 7)p + 11 = 11p + 11 = 11(p + 1)

Look at it this way: If p = 1, then 7p = 7. What plus 7 equals -3? Adding 7 to -10 would equal -3, so all we have to figure out is what times 5 would equal -10. 5 times -2 would equal -10 so q equals -2.

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