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What is 81X4?

Anonymous

∙ 9y ago

Updated: 9/25/2023

x=81

Myrtice Paucek ∙

Lvl 9

∙ 2y ago

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How do you expand 3x minus 5 to the fifth power using the binomial theorem?

(3x - 5)5= (3x + -5)5= (5C0)(3x)5(-50)+(5C1)(3x)4(-5)1+(5C2)(3x)3(-5)2+(5C3)(3x)2(-5)3+(5C4)(3x)1(-5)4+(5C5)(3x)0(-5)5= (1)(243x5)(1)+(5)(81x4)(-5)+(10)(27x3)(25)+(10)(9x2)(-125)+(5)(3x)(625)+(1)(1)(-3125)= 243x5 - 2,025x4 + 6,750x3 - 11,250x2 + 9,375x - 3125

Related Questions

9x squared plus 7 x 9x squared -7?

(9x2 + 7)(9x2 - 7) = 81x4 - 49

What is sqr 81x4?

sqrt(81 x 4) = sqrt(81) X sqrt(4) = 9 X 2 18

What the sum 2 cubed and 3 squared?

2 cubed is 2x2 and 3 squared is 3x3x3x3, you can multiply 2x2 which equals 4 and 3x3x3x3 equals 81, (because 3x3 is 9 and 3x3 shows up 2 times you multiply 9,2 times) so then you have to multiply 81x4 81 x 4 ____ 324

How do you expand 3x minus 5 to the fifth power using the binomial theorem?

(3x - 5)5= (3x + -5)5= (5C0)(3x)5(-50)+(5C1)(3x)4(-5)1+(5C2)(3x)3(-5)2+(5C3)(3x)2(-5)3+(5C4)(3x)1(-5)4+(5C5)(3x)0(-5)5= (1)(243x5)(1)+(5)(81x4)(-5)+(10)(27x3)(25)+(10)(9x2)(-125)+(5)(3x)(625)+(1)(1)(-3125)= 243x5 - 2,025x4 + 6,750x3 - 11,250x2 + 9,375x - 3125

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