(9x2 + 7)(9x2 - 7) = 81x4 - 49
It is: (x-2)(x-7) when factored
Integral : 9x + 8 = 9(x squared)/2 + 8x Differential : 9x +8 = 9
x^(2) + 9x + 14 = 0 To solve. Since 'x^(2)' has a coefficient of '1' ( not shown), then look at the constant' 14'. Look for two numbers that multiply to ;14; and add to ;9; . To do this write down all the factors of '14' . ; 1,2,7,14. . Select '2' & '7' . 2 X 7 = 14 & 2 + 7 = 9. Hence , factoring ( x + 2)( x + 7) = 0 Hence the solutions are x = -2 & x = -7 .
2x+3=9x 3=9x-2x 3=7x x=3/7
It is (x+6)(x+7) when factored
(9x + 7)(x - 2)
It is: (x-2)(x-7) when factored
are you sure from this equation ? x^2 + 9x + 11 ____________ = zero x + 7 or there is no zero ?? please be sure from the x^2 + 9x + 11 ???
(x+1)(x+8)
x2 - 9x + 8 = (x-1)(x-8)
x2-9x can be factored by taking x out of each term x(x-9)
It is a quadratic equation in x.
If: 9x+7 = 6x+25 Then: x = 6
If you mean: 2x^2 +9x +7 then it is (2x+7)(x+1) when factored
You can solve this as a quadratic (it's degree is 2). 9x^2+2x=7 9x^2+2x-7=0 (Hey, a quadratic!) (9x-7)(x+1)=0 Thus, the solutions for x to this problem are -1, and 7/9.
It is (x-1)(x-8) when factored
(x + 12)(x - 3)