126
To solve (2 \times 3^2), first calculate (3^2), which is (9). Then, multiply (2) by (9): (2 \times 9 = 18). Therefore, (2 \times 3^2 = 18).
You can use the fact that 4 is equal to 2 times 2 and the fact that 9 can be expressed as 3 times 3. By multiplying these facts, you can calculate 4 times 9 as follows: 4 times 9 equals (2 times 2) times (3 times 3). This can be rearranged to (2 times 3) times (2 times 3), which simplifies to 6 times 6, giving you 36 as the answer.
9*3=36-3=33*2=66%2=33
3 times 3 times 3 times 2 times 2 is the prime factorization of 108 because: 3 times 3 = 9, 9 times 3 = 27, 27 times 2 = 54, 54 times 2 = 108
9 multiplied by 2/3 is 6
I assume that you mean integers: 3 times 3 equals 9, as does 9 times 1. Also -3 times -3 and -9 times -1.
The greatest common factor of 45 and 72 is 9. 45- 3 times 3 times 5 75- 2 times 2 times 2 times 3 times 3 3 times 3 = 9, the GCF
To calculate (1) and (2) thirds times (9), first convert (1) and (2) thirds into an improper fraction. This gives you (\frac{5}{3}). Then, multiply (\frac{5}{3}) by (9): [ \frac{5}{3} \times 9 = \frac{5 \times 9}{3} = \frac{45}{3} = 15. ] So, (1) and (2) thirds times (9) equals (15).
6*10^9 / 2*10^3 = (6/2) * 10^9 / 10^2 = 3*10^(9-3) = 3*10^6 or 3 million.
3 and 2/3 times.
You can express 81 as a power in several ways: ( 81 = 3^4 ) because ( 3 \times 3 \times 3 \times 3 = 81 ). ( 81 = 9^2 ) since ( 9 \times 9 = 81 ) and ( 9 ) can be rewritten as ( 3^2 ). ( 81 = (3^2)^2 ) which simplifies to ( 3^{2 \times 2} = 3^4 ). Thus, all representations confirm that ( 81 ) can be expressed as a power in different forms.
9/10 × 2/3 = 3/5