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Q: What is 9x squared plus 16 when factoring?

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9x squared plus 16 = 0 factored is plus and minus 4/3 i.

(9x)2 +9x/(45x)2 +81= 9+9x/86

Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2

(9x2 + 7)(9x2 - 7) = 81x4 - 49

(9x + 7)(x - 2)

This is (3x +2)2 so if x is an integer/3, this expression is the square of an integer so cannot be prime. Anything else, and it's not even an integer.

81x2 + 72x + 16 = 81x2 + 36x + 36x + 16 = 9x(9x + 4) + 4(9x + 4) = (9x + 4)2

9x(x2+3x-10)

9x squared-15x squared = -6

If you mean: x squared+9x+14 = 0 then by using the quadratic equation formula x = -2 or x = -7

2x2+9x+9 = (2x+3)(x+3) when factored

Type your answer here... 81

(3x - y+ 2)(3x + y + 2)

9x2 + 8x - 1 = (9x - 1)(x + 1)

Integral : 9x + 8 = 9(x squared)/2 + 8x Differential : 9x +8 = 9

If: x+16 = 9x then x = 2

It is a quadratic equation in x.

(x+1)(x+8)

3(x2 + 3x + 1)

(2x+3)(x+3)

x2 - 9x + 8 = (x-1)(x-8)

2x2-9x+4 = (2x-1)(x-4) when factored

If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.

In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.

(3x-4)(3x+4)