A^8 or A raised to the power of 8.
The expression (2 \times 3 \times 3 \times 3 \times 5) can be rewritten using exponents as (2^1 \times 3^3 \times 5^1). This indicates that 2 is raised to the power of 1, 3 is raised to the power of 3, and 5 is raised to the power of 1.
A number raised to the power "a" is multiplied by itself "a" times. For example, 5 raised to the power 3 is 5x5x5=125. 2 raised to the power 5 is 2x2x2x2x2=32.
Actually, (3) raised to the (5)th power equals (243) because (3^5) is calculated as (3 \times 3 \times 3 \times 3 \times 3), which equals (243). To break it down, (3^2 = 9), (3^3 = 27), (3^4 = 81), and finally (3^5 = 243). Thus, (3^5 = 243) is correct.
The number 200 can be expressed in exponents as (2^3 \times 5^2). This means that 200 is equal to (2) raised to the power of (3) multiplied by (5) raised to the power of (2). In exponential form, this highlights its prime factorization.
5
The expression (2 \times 3 \times 3 \times 3 \times 5) can be rewritten using exponents as (2^1 \times 3^3 \times 5^1). This indicates that 2 is raised to the power of 1, 3 is raised to the power of 3, and 5 is raised to the power of 1.
A number raised to the power "a" is multiplied by itself "a" times. For example, 5 raised to the power 3 is 5x5x5=125. 2 raised to the power 5 is 2x2x2x2x2=32.
Actually, (3) raised to the (5)th power equals (243) because (3^5) is calculated as (3 \times 3 \times 3 \times 3 \times 3), which equals (243). To break it down, (3^2 = 9), (3^3 = 27), (3^4 = 81), and finally (3^5 = 243). Thus, (3^5 = 243) is correct.
The number 200 can be expressed in exponents as (2^3 \times 5^2). This means that 200 is equal to (2) raised to the power of (3) multiplied by (5) raised to the power of (2). In exponential form, this highlights its prime factorization.
5
-2
As a product of its prime factors: 2*2*2*3*3*5 = 360
The answer is one.
If it's the same number, it's that number to the fifth power.
Negative 3 raised to the power of 5 is equal to -243.
To write the expression (2 \times 2 \times 3 \times 3 \times 5 \times 5) using indices, you group the identical factors together. This gives you (2^2 \times 3^2 \times 5^2). Each base number is raised to the power of the number of times it appears in the product.
As the number being raised to the powers is the same, the powers can be added together and the answer is the number raised to this power: 56 x 5-2 = 56 + -2 = 54 = 625