6.4 x 10-9
MgCl2 aq plus Zn s is the oxidation half-reaction for Mg s plus ZnCl2 aq.
45-5x = 5x+55 -5x-5x = 55-45 -10x = 10 x = -1
2X2+5x-12 4+5x-12 -8+5x 5x-8
To do this equation, there would have to be an = in it. If you mean 5x-2y=4, then: 5x-2y=4 -5x -5x = -2y=4-5x Hope this helped!
MgCl2 is added to the lysis buffer since Mg2+ ions are co-factors for the enzyme used in the lysis buffer. This enzyme requires magnesium ions in order to function properly.
1 ml of 5X TE in 4ml distilled water (or).......if u want 100 ml just multiply 1 and 4 with 20....you will get 20 ml 5X TE in 80 ml distilled water
-2.37
-2.37 v
Mgnesium lost two electrons (reduction).
0.34 - (-2.37) you're welcome.
-2.37 v
Mg equals Mg2+ plus 2e-
-2.37 v
The overall voltage for a redox reaction with the half reactions Mg s -- Mg2 plus plus 2e- and Cu2 plus -- Cu is 76 V.
It is called a buffer. Depending on the reaction and reactants it could be any kind of acid or base that has the right characteristics to play the role of a buffer.
obviously