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Q: What is N-3 equals 6?

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If: n3 = 8 Then: n = 2

2

6+N3 is the sum of N*3 then you add six. 6*N3 is you multiply 6 times three times N times three.

n x n2 = n3

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Let any number be n:- n3/n3 = n*n*n/n*n*n = 1 And in index form: n3/n3 = n3-3 = n0 = 1

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9/6 = 21/n3/2 = 21/n Since 3 x 7 = 21, then n must be 14 (2 x 7) and we have:3/2 = 21/14 or 9/6 = 21/14.

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n3 + 1 = n3 + 13 = (n + 1)(n2 - n + 12) = (n + 1)(n2 - n + 1)

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