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What is The law that states the effort force times the distance the effort moves is equal to the resistance times the distance the resistance moves?
Wiki User
∙ 12y ago
At each end, (the force) x (the distance) defines the quantity of work, or energy.
They're known to be equal because of the law of conservation of energy.
Wiki User
∙ 12y ago
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Why is work input equal to the effort force times the effort distance?
That's the definition of "work" ... (force exerted) times (distance through which the force acts). If you push against the end of a lever with a force 'F' and move it through a distance 'D', then (F x D) is the work you put into the lever.
Formula of time?
You can find many formulas in which time is one of the variables. For example, the distance formula states that distance is equal to speed multiplied by the time. You can find time by saying that it is equal to distance divided by speed.
What is 2 km 90 m?
It is a measure of distance, equal to 2.09 kilometres.It is a measure of distance, equal to 2.09 kilometres.It is a measure of distance, equal to 2.09 kilometres.It is a measure of distance, equal to 2.09 kilometres.
What Distance Is Equal To 1000?
The distance 1 kilometre is equal to 1000 metres
Under what condition the distance and displacement are equal?
The magnitude of displacement is equal to distance traveled when motion is in a straight line.
Is effort diastance is equal to the resistance distance?
You can make any relationship you want between the effort distance and the load (resistance) distance. If you make them equal, then your lever has no mechanical advantage.
With regard to the object-lifting examples traced in lesson3 the ima is equal to the distance divided by the distance?
Effort, resistance
How do first class levers work?
distance from fulcrum to point of effort is de distance from fulcrum to point of resistance is dr Force applied is called the effort, Fe The weight of the object to resistance, Fr Ignoring the weight of the lever itself ... IDEALLY Fede = Frdr Effort ---- fulcrum ---- resistance (not necessarily equal lengths) In this illustration, effort pushes down on left, resistance is lifted up on right.
With regard to the object-lifting the IMA is equal to the?
effort, resistance
If the effort force for lever is 50 Newtons then what would be the resistance force Assme no friction IMAAMA?
the resistence force will be equal to 50 Newtons times the distance from the point of the effort force to the object along the lever.
How do you find the effort force if you already have the load force and the distance moved by load force?
work (effort) equals load times distance
With regard to the object-lifting examples traced in lesson 3 IMA is equal to the --distance divided by the --distance?
effort, resistence
With regard to the object-lifting examples traced in lesson 3 the ima is equal to the distance divided by the distance?
effort, resistence
How does the position of the fulcrum and the location of the load affect the amount of effort force you must exert to lift the load?
To do this you first have to calculate your ideal mechanical advantage (IMA). The IMA is equal to the effort distance (the distance from the fulcrum to where you will apply the effort) divided by the load distance (the distance from the fulcrum to the load). You can then set your IMA equal to your acutal mechanical advatage (AMA) which assumes 100% efficiency. The AMA is equal to the load force (the weight of what you are lifting) divided by the effort force (the # you are looking for). So, for example, if your IMA is 5 and your load force is 500 lbs: 5=500/effort force. Therefore the effort force would be 100 pounds.
Is Ohm's law states that voltage in a circuit is equal to resistance times current true or false?
True. Ohm's law states the voltage is resistance times current.
The efficiency of a real machine?
Efficiency is equal to the ratio of work input to work output; for an ideal machine this ratio is equal to 1 or 100%. For a real machine this ratio is always less than 1 because some of the work input is used to overcome mechanical friction within the machine which does not contribute to the work output of the machine.
Why is work input equal to the effort force times the effort distance?
That's the definition of "work" ... (force exerted) times (distance through which the force acts). If you push against the end of a lever with a force 'F' and move it through a distance 'D', then (F x D) is the work you put into the lever.
