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Q: What is a conjugate number of 2 plus square root of 5?

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x plus the square root of 2

If the square root of a number is irrational, it is its own conjugate. sqrt(13)*sqrt(13) = 13 and you no longer have an irrational!

a+ square root of b has a conjugate a- square root of b and this is used rationalize the denominator when it contains a square root. If we want to multiply 5 x square root of 10 by something to get rid of the radical you can multiply it by square root of 10. But if we look at 5x( square root of 10 as ) 0+ 5x square root of 10 then the conjugate would be -5x square root of 10

you cant take the square root of a negative number

irrational

Nothing. You cannot have a square root of a negative number. The square root of negative one is called i, but i is an imaginary number. It does not exist and does not follow the properties of real numbers. (For example, if a and b are positive, then the square root of a times the square root of b is the square root of ab. But the square root of -7 is not the square root of 7 times i.)

square root of 27 plus the square root of 75

The square root of 27 plus the square root of 5 = 7.4322204

If this is supposed to be a riddle, it's not a very good one. The square root of the number whose square root is two is, obviously, two.

Since infinity is not a defined number, it is impossible to have a square root of it. its infinity!

They are the complex conjugate numbers +/- 3*sqrt(2)*i where i is the imaginary square root of -1.

The complex conjugate pair, -6 -8.7178i and -6 +8.7178i where i is the imaginary square root of -1.The complex conjugate pair -6 -8.7178i and -6 +8.7178i where i is the imaginary square root of -1.

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