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If the square root of a number is irrational, it is its own conjugate.

sqrt(13)*sqrt(13) = 13 and you no longer have an irrational!

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Q: What is the conjugate of square root of 13?

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a+ square root of b has a conjugate a- square root of b and this is used rationalize the denominator when it contains a square root. If we want to multiply 5 x square root of 10 by something to get rid of the radical you can multiply it by square root of 10. But if we look at 5x( square root of 10 as ) 0+ 5x square root of 10 then the conjugate would be -5x square root of 10

13, is not the square root of 156, but the best i can give you is that 13 is the square root of 169 and 14 is the square root of 196.

This is related to the technique used to eliminate square roots from the denominator. If, for example, the denominator is 4 + root(3), you multiply both numerator and denominator by 4 - root(3). In this case, "4 - root(3)" is said to be the "conjugate" of "4 + root(3)". When doing this, there will be no more square roots in the denominator - but of course, you'll instead have a square root in the numerator.

169. 13 x 13 = 169. square root of 169 = 13.

The square root of 169 = ± 13

Related questions

a+ square root of b has a conjugate a- square root of b and this is used rationalize the denominator when it contains a square root. If we want to multiply 5 x square root of 10 by something to get rid of the radical you can multiply it by square root of 10. But if we look at 5x( square root of 10 as ) 0+ 5x square root of 10 then the conjugate would be -5x square root of 10

x plus the square root of 2

[ 2 minus square root of 5 ] is the only one.

The complex conjugate pair, -6 -8.7178i and -6 +8.7178i where i is the imaginary square root of -1.The complex conjugate pair -6 -8.7178i and -6 +8.7178i where i is the imaginary square root of -1.

The square root of 13 = 3.605551275....

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the square root of 13 x 13 is 13

Yes. For example, the conjugate of (square root of 2 + square root of 3) is (square root of 2 - square root of 3).

-13 or +13 are both square root of 169, but we often use the positive square root, 13, as the principal square root.

13, is not the square root of 156, but the best i can give you is that 13 is the square root of 169 and 14 is the square root of 196.

This is related to the technique used to eliminate square roots from the denominator. If, for example, the denominator is 4 + root(3), you multiply both numerator and denominator by 4 - root(3). In this case, "4 - root(3)" is said to be the "conjugate" of "4 + root(3)". When doing this, there will be no more square roots in the denominator - but of course, you'll instead have a square root in the numerator.

The square root of 13 simplified is 3.6