The answer will depend on what DF is!
The answer depends on the degrees of freedom (df). If the df > 1 then the mean is 0, and the standard deviation, for df > 2, is sqrt[df/(df - 2)].
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To determine if triangles ABC and DEF are similar, we can use the side lengths given. The ratios of the corresponding sides must be equal. For triangle ABC, the sides are AB = 4, AC = 6, and the unknown BC, while for triangle DEF, the sides are DE = 8, DF = 12, and the unknown EF. The ratio of AB to DE is 4/8 = 1/2, and the ratio of AC to DF is 6/12 = 1/2, which are equal. Therefore, triangles ABC and DEF are similar by the Side-Side-Side (SSS) similarity criterion.
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DragonFable
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The answer will depend on what DF is!
We cannot possibly answer this - as there'e not enough information in the question.
DF is not a valid ISO-3166-1 country code. There is no top-level Internet domain .df
We can * Assume that 24 is the hypotenuse - the side opposite the right angle - then * 72 + df2 = 242 * Or 49 + df2 = 576 which leads us to df2 = 527 which leads to df = 22.956 Or we can * Assume that df is the hypotenuse - the side opposite the right angle - then * 72 + 242 = df2 * Or 49 + 576 = df2 which leads to 625 which leads to df = 25 As 25 is a whole number it is most likely the answer to the problem, but the other answer is equally valud, given the data presented.