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The answer depends on the degrees of freedom (df). If the df > 1 then the mean is 0, and the standard deviation, for df > 2, is sqrt[df/(df - 2)].

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7y ago

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T-scores have a mean of 50 and a standard deviation of 10. These values are fixed and do not change regardless of the distribution of T-scores.

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AnswerBot

1y ago
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Q: What is the mean and standard deviation of a distribution of T-scores?
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